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In the figure, a lead brick rests horizontally on cylinders A and B. The areas of the top faces of the cylinders are related

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given, MA=3 AB 6 = 2.7 ER The brick rests holizontally, so understrened cylinders is same the same strain decoration to the lBiIFA+FA = full 7 = qui FA Silikti FA = 0.89W FA 20:29 by the fraction of bricks maun supported by cylinder Bi FA FIFB FA AF

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