A jogger accelerates from rest to 5.47 m/s in 2.18 s. A car
accelerates from 21.2 to 32.2 m/s also in 2.18 s.
(a) Find the magnitude of the acceleration of the
jogger. (b) Determine the magnitude of the
acceleration of the car. (c) How much further does
the car travel than the jogger during the 2.18 s?
A jogger accelerates from rest to 5.47 m/s in 2.18 s. A car accelerates from 21.2...
A jogger accelerates from rest to 5.84 m/s in 3.02 s. A car accelerates from 24.4 to 44.7 m/s also in 3.02 s. (a) Find the magnitude of the acceleration of the jogger. (b) Determine the magnitude of the acceleration of the car. (c) How much further does the car travel than the jogger during the 3.02 s?
Please explain A jogger accelerates from rest to 4.67 m/s in 3.69 s. A car accelerates from 19.7 to 34.9 m/s also in 3.69 s. (a) Find the magnitude of the acceleration of the jogger. (b) Determine the magnitude of the acceleration of the car. (c) How much further does the car travel than the jogger during the 3.69 s? (a) Number (b) Number (C) Number Units Units Units
Chapter 02, Problem 25 A jogger accelerates from rest to 3.11 m/s in 2.16 s. A car accelerates from 19.4 to 31.4 m/s also in 2.16 s. (a) Find the magnitude of the acceleration of the jogger. (b) Determine the magnitude of the acceleration of the car. (c) How much further does the car travel than the jogger during the 2.16 s? (a) Number Units (b) Number Units (c) Number Units
A jogger accelerates from rest to 3.1 m/s in 2.4 s. A car accelerates from 35.0 to 42.0 m/s also in 2.4 s. (a) Find the acceleration (magnitude only) of the jogger. m/s2 (b) Determine the acceleration (magnitude only) of the car. m/s2 c) If so, how much farther?
A car accelerates uniformly from rest and reaches a speed of 21.2 m/s in 8.90 s. Assume the diameter of a tire is 57.9 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second? rev/s
A car accelerates from rest at a constant rate of 2.0 m/s for 5.0 s. (a) What is the speed of the car at the end of that time? (b) How far does the car travel in this time? MacBook Pro
A car accelerates from rest at a constant rate of 2.0 m/s for 5.0 s. (a) What is the speed of the car at the end of that time? (b) How far does the car travel in this time? MacBook Pro
1 (a) A car accelerates from rest to a speed of 10.9 m/s in 8.4 seconds. Find the magnitude of the average acceleration. (b) If I accelerate for 5.3 seconds in my car at 2.6 m/s2 when I have an initial velocity of 20.9 m/s, what final velocity do I have? (c) If I apply an acceleration in the opposite direction to my initial velocity for 7.4 seconds of -3.2 m/s2 when I have an initial velocity of +21.6 m/s,...
A car accelerates from rest with a constant acceleration of 1.5m/s^2 for 14 seconds . the car then continues traveling at the constant velocity with the speed it achieved after the 14 seconds of acceleration . it travels at this constant velocity for an additional 25 seconds. how far did the car travel during this whole motion?
A drag racer starts her car from rest and accelerates at 10.4 m/s for a distance of 395 m. (a) How long did it take the race car to travel this distance? 7.5 x Your response differs from the correct answer by more than 10%. Double check you (b) What is the speed of the race car at the end of the run? (No Response) m/s