Question

QUESTION 4 15 points Save A truck of mass 5m traveling with a speed v collides with a stationary car of mass m. If the collision is perfectly Inelastic, what is the joint speed of the car and truck immediately after the collision? Or OV 6 OS QUESTION 5 15 points Save An Two objects collide and bounce apart. If the total kinetic energy of the objects is the same before and after the collision, what type of collision is this? perfectly inelastic inelastic it is not possible to say what type of collision this is elastic QUESTION 6 15 points Save Ans What is the magnitude of the momentum of an object of mass 6.52 kg when moving with a speed of 10.2 m/s, in units of kg.m/s?

Answer 1

1) As, linear momentum = mass × velocity of the object

Initial momentum of the car = 827 × 16.1 = 13314.7 kg.m/s

Initial momentum of the second car = 668 × (-11.2) = - 7481.6 kg.m/s

Total initial momentum of the system = 13314.7 + (-7481.6)

= 5833.1 kg.m/s

As the collision is perfectly inelastic so both the cars move with the same velocity after collision

Let v' be the combined velocity of the two cars after collision

Total final momentem of the system = (827+668)×v' = 1495v'

Using conservation of linear momentum

Total final momentum of the system = total initial momentum

1495v' = 5833.1

v' = 3.90 m/s

2). Ans : between 0 to v

Explanation:

Let m be the mass of each car

v = speed of the first car before collision

Total initial momentum = mv + m×0 = mv

{ As the second car is at rest so its speed is zero}

Let v' = combined velocity of the two cars after collision

Final momentum of the system = (m+m)v' = 2mv'

Using conservation of linear momentum

Total final momentum = total initial momentum

2mv' = mv

v' = v/2

3). Impulse = magnitude of average force × time

Magnitude of average force = Impulse / time

Magnitude of average force = 24.3 / 0.0595

Magnitude of average force = 408.40 N

4). Ans: 5v/6

Explanation:

Initial momentum of the truck = 5m×v

Initial momentum of the car = m×0 = 0

{As the car is at rest so its velocity is zero}

Total initial momentum of the system = 5mv + 0 = 5mv

As the collision is perfectly inelastic so the truck and the car stick together after collision

Let v' = combined velocity of the truck and the car after collision

Final momentum of the truck = 5mv'

Final momentum of the car = mv'

Total final momentum of the system = 5mv' + mv' = 6mv'

As there is no external force acting so total momentum of the system remains conserved

Total final momentum = Total initial momentum

6mv' = 5mv

v' = 5v/6

5) Ans: elastic

Explanation:

Total kinetic energy of the system remains conserved during elastic collision. As the kinetic energy is conserved therefore the collision is elastic.

6). Magnitude of linear momentum of a moving body is given by

Linear momentum = mass of the object × magnitude of velocity of the object

Hence

Linear momentum = 6.52 kg × 10.2 m/s

Linear momentum = 66.504 kg.m/s