Question

articular gas exerts a pressure of 731 mmHg. What is this pressure in units of atmospheres? 12. A particular ga 5.48 x 10' atm b. 5.63 x 10 atm c. 721 atm d. 0.974 atm e. 0.961 atm 13. A flexible container is charged with a certain volume of gas at 315.0 K. Under conditions of constant pressure and moles of gas, how does the temperature of the gas change when the volume is tripled? a. The temperature increases by a factor of three. b. The temperature decreases by a factor of four. c. The temperature decreases by a factor of two d. The temperature increases by a factor of four e. The temperature increases by a factor of two 14. A gas occupying a volume of 1.50 L exerts a pressure of 700 mmHg at 200°C. Which mathematical expression gives the correct prestare at 3.50 L and 350°C? “700 mmHg x 1.302473 K 3.50 L 623 1.502 700 mmHg x 623 3.50 473K 473K 700 mmHg x 623 K 473 K 350°C c. 700 mmHg * 1.50 L 623 d. 700 mmHg * 200°C 15. Calculate the mass, in grams, of 2.74 L of CO gas measured at 33°C and 945 mmHg (R -0.08206 L'atm-K.moll, 1 atm = 760 mmHg). A) 0.263 g B) 2.46 g C) 35.2 g D) 3.80 g E) 206 g

Answer 1

- laturi = 760 mming 731 mmHg = 73) mutta tatima = 0.9618 alin ommuta - Answer @ V = V T, = 3/5.08 p = 3v Ta=? y = 122 at constant pressure * and mols fuga جم/لام علم کی - T2 = 3 x 315k = 945.0k Temperature increases by a factor of Answer:- @ Three - 14 PV = P2 V 2 ☺ la = P x Thea = 700 women, als02 62.34 99473K 3.502 Answer : No of mols (n) = pv P=945 = 1.243 atm t naman n = 1243X274 T= 332=300k -0.08206 x 306 (0228 480 = 0.1356 mos R = 0.08206 W = 3.80 g Ans :D NO f mols in V=2.742 zork