Question

scientific calculator - Google Search MyDelta Portal Chapter E MAT2323 001 (MSVCC) Assignments Chapter 9 Fall 2019 online Chapter 9 Home Modules Statistics Online Fall 2019 MyLab and Master- ing Save NetTutor Homework: Chapter 9 Score: 0.25 of 1 pt + 8 of 9 (8 complete) 9.3.12-T HW Score: 67.06%, 6.04 of 9... Grades Question Help Quizzes Bookshelf Smarter Proctoring The table shows the total square footage (in billions) of retailing space at shopping centers and their sales in billions of dollars) for 10 years. The equation of the regression line is y 515.293x - 1685.037. Complete parts and Total Square 4.9 5.1 5.2 5.4 5.5 5.7 5.8 5.9 15962 Footage, Sales, y 1892.4943.998161069.1 1114 2 12128 1275.7 1334 61447.815278 (b) Find the standard error of estimates, and interpret the result. Policies and Informa- tion Student Profile (Round the final answer to three decimal places as needed. Round all intermediate values to four decimal place needed.) Enrollment Tool Enter your answer in the answer box and then click Check Answer. Check Answer Clear All part remaining

Answer 1

Y	X	(Xi - $\bar{X}$ )	(Yi - $\bar{Y}$ )	(Xi - $\bar{X}$ )2	(Yi - $\bar{Y}$ )2	$\hat{Y}$	(Yi - $\hat{Y}$ )2
892.4	4.9	-0.66	-287.59	0.4356	82708.0081	843.14909	2425.6521
943.9	5.1	-0.46	-236.09	0.2116	55738.4881	945.2221	1.7479
981.6	5.2	-0.36	-198.39	0.1296	39358.5921	996.2586	214.8746
1069.1	5.4	-0.16	-110.89	0.0256	12296.5921	1098.3316	854.4864
1114.2	5.5	-0.06	-65.79	0.0036	4328.3241	1149.3681	1236.7952
1212.8	5.7	0.14	32.81	0.0196	1076.4961	1251.4412	1493.1423
1275.7	5.8	0.24	95.71	0.0576	9160.4041	1302.4777	717.0452
1334.6	5.9	0.34	154.61	0.1156	23904.2521	1353.5142	357.7469
1447.8	5.9	0.34	267.81	0.1156	71722.1961	1353.5142	8889.8121
1527.8	6.2	0.64	347.81	0.4096	120971.761	1506.6237	448.4357
11799.9	55.6	-	-	1.524	421262.149	-	16639.7384

$\bar{Y}$ = 11799.9/10 = 1179.99

$\bar{X}$ = 55.6/10 = 5.56

Our assumption model is,

Y = $\beta_{0}$ + $\beta_{1}$ x

where ,

Σ(X; – X) (Υ, – Υ) Σ(X, - X)2

= 777.7964 /1.524 = 510.3651

$\beta_{0}$ =

Y - B1X

= 1179.99-5.56*510.3651 = -1657.6399

We know,

1.1 SE(Bo) = o (-+ Vin X2 * ) Sri

SE(B1) =

Now,

A-80C = 0

= 45.6067

Now, standard error of estimates are,

SE(B) = 45.6067*11 5.562 + * V 10 * 1.524

= 205.911

SE(B1) = 45.6067 V1.524

= 36.943

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