You start with 23.00g of aluminum and 55.00g of NH4ClO4. What is the limiting reagent? 10Al(s)...
You start with 23.00g of aluminum and 55.00g of NH4ClO4. What is the limiting reagent? 10Al(s) + 6NH4ClO4(s) --> 4Al2O3(s) + 2AlCl3(s) + 12H2O(g) + 3N2(g).
Homework Answers
10Al(s) + 6NH4ClO4(s) --> 4Al2O3(s) + 2AlCl3(s) + 12H2O(g) + 3N2(g).
according to balanced reaction
10x 27 g AL reacts with 6 x 117.49 g NH4ClO4
23.0 g Al reacts with 23 x 6 x 117.49 / 10 x 27 = 60.05 g NH4ClO4
but we have 55.0 g NH4ClO4.
so limiting reagent = NH4ClO4
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