What is happening to the electron in the tube to make it deflect more when Vd...
What is happening to the electron in the tube to make it deflect more when Vd is increased? What is happening to the electron in the tube to make it deflect more when Vaccel -1 is increased (means electron is deflected less when Vaccel is increased) ?
Homework Answers
We know that Vacc is the accelerating potential. The energy balance is such that
1/2 m v^2 = e Vacc
The electon beam get deflected by the electric field between the plates which exerts a force Fe, the voltage thus produced is the deflection voltage.
Its the magnetic field strengthwhich causes the deflection of electron beam, So by increasing the Vacc, the velocity of the beam will increase, not the deflection.
Add Answer to:
What is happening to the electron in the tube to make it deflect
more when Vd...
please answer these two questions A) Do these two graphs support the theory as summarized in...
please answer these two questions
A) Do these two graphs support the theory as summarized in (8)?
Explain what it is about the plots that let you say this?.
B) Does (8) make sense? To answer this, discuss the physics of
why the electrons deflect more or less for each of the two trials.
That is, what is happening to the electron in the tube to make it
deflect more when Vd is increased? What is happening to the
electron...
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d =1.5-cm-wide region of uniform magnetic field in the figure(Figure 1). Part A What field strength will deflect the electron by 9 = 11 °?
(3) An electron is projected with horizontal velocity v.-5x10s m/s into a uniform electric field of...
(3) An electron is projected with horizontal velocity v.-5x10s m/s into a uniform electric field of magnitude 4000 N/C pointed upwards that is presented over a horizontal distance of 2 cm (a) Find the magnitude and direction of the force due to the electric field. Is it justifiable to ignore the gravitational force? (b) By what vertical distance will the electron be deflected when it exits the field? (c) Find the angle with respect to horizontal as it I JJ....
Physics questionPlease, show work.An electron in a cathode-ray tube is accelerated through a potential...
Physics questionPlease, show work.An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 2.3-cm-wide region of uniform magnetic field in the figure(Figure 1.).Part A What field strength will deflect the electron by theta = 14 degree? Express your answer to two significant figures and include the appropriate units.
(3) An electron is projected with horizontal velocity vo 5x10s m/s into a uniform electric field...
(3) An electron is projected with horizontal velocity vo 5x10s m/s into a uniform electric field of magnitude 4000 N/C pointed upwards that is presented over a horizontal distance of 2 cm. (a) Find the magnitude and direction of the force due to the electric field. Is it justifiable to ignore the gravitational force? (b) By what vertical distance will the electron be deflected when it exits the field? (c) Find the angle with respect to horizontal as it leaves...
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then...
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 1.8 cm wide region of uniform magnetic field in the figure. x x x x x x x x x OV 10 kV What field strength will deflect the electron by = 11 degrees? Express your answer in mT. B= Preview mT
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV then passes through the d=2.3-cm-wide region of uniform magnetic field in the figure
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV then passes through the d=2.3-cm-wide region of uniform magnetic field in the figure(Figure 1) Part A What field strength will deflect the electron by θ = 11°?
please show calculations and explanation when necessary In a cathode ray tube, electrons with a velocity...
please show calculations and explanation when
necessary
In a cathode ray tube, electrons with a velocity of 4.5 x 10 m/s in the k direction are deflected by a magnetic field of B = (1.4 x 10-4 T)i - (2.6 x 10-4 T)ý. a) What is the force (magnitude and direction) on a single electron? b) A 10 cm long wire is placed in a magnetic field of the same magnitude, such that it makes a 30° angle with the...
Can someone explain what is happening in this diagram why are there two exits for pressure P in the actual tube. Pitot-static tube To manometer Po Bernoulli's equation along AO: 2 Pitot-stat...
Can someone explain what is happening in this diagram why are
there two exits for pressure P in the actual tube.
Pitot-static tube To manometer Po Bernoulli's equation along AO: 2
Pitot-static tube To manometer Po Bernoulli's equation along AO: 2
An electron with kinetic energy is moving to the right along the axis of a cathode-ray tube as...
An electron withkinetic energy of 6.0 10-16 J is moving to the right along the axis of a cathode-ray tube as shown below. There is an electric field = (2.0 104 N/C) in the regionbetween the deflection plates. Everywhere else, = 0.(a) How far is the electron from the axis of the tube when it reaches the end of the plates? (mm)(b) At what angle is the electron moving with respect to the axis?(c) At what distance from the axis...
please answer these two questions
A) Do these two graphs support the theory as summarized in (8)?
Explain what it is about the plots that let you say this?.
B) Does (8) make sense? To answer this, discuss the physics of
why the electrons deflect more or less for each of the two trials.
That is, what is happening to the electron in the tube to make it
deflect more when Vd is increased? What is happening to the
electron...
(3) An electron is projected with horizontal velocity v.-5x10s m/s into a uniform electric field of magnitude 4000 N/C pointed upwards that is presented over a horizontal distance of 2 cm (a) Find the magnitude and direction of the force due to the electric field. Is it justifiable to ignore the gravitational force? (b) By what vertical distance will the electron be deflected when it exits the field? (c) Find the angle with respect to horizontal as it I JJ....
Physics questionPlease, show work.An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 2.3-cm-wide region of uniform magnetic field in the figure(Figure 1.).Part A What field strength will deflect the electron by theta = 14 degree? Express your answer to two significant figures and include the appropriate units.
(3) An electron is projected with horizontal velocity vo 5x10s m/s into a uniform electric field of magnitude 4000 N/C pointed upwards that is presented over a horizontal distance of 2 cm. (a) Find the magnitude and direction of the force due to the electric field. Is it justifiable to ignore the gravitational force? (b) By what vertical distance will the electron be deflected when it exits the field? (c) Find the angle with respect to horizontal as it leaves...
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 1.8 cm wide region of uniform magnetic field in the figure. x x x x x x x x x OV 10 kV What field strength will deflect the electron by = 11 degrees? Express your answer in mT. B= Preview mT
please show calculations and explanation when
necessary
In a cathode ray tube, electrons with a velocity of 4.5 x 10 m/s in the k direction are deflected by a magnetic field of B = (1.4 x 10-4 T)i - (2.6 x 10-4 T)ý. a) What is the force (magnitude and direction) on a single electron? b) A 10 cm long wire is placed in a magnetic field of the same magnitude, such that it makes a 30° angle with the...
Can someone explain what is happening in this diagram why are
there two exits for pressure P in the actual tube.
Pitot-static tube To manometer Po Bernoulli's equation along AO: 2
Pitot-static tube To manometer Po Bernoulli's equation along AO: 2
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