BaCl2 +Na2SO4 = BaSO4(s) + 2Na +2Cl Calculate the mass of the limiting reagent that reacted...
BaCl2 +Na2SO4 = BaSO4(s) + 2Na +2Cl
Calculate the mass of the limiting reagent that reacted in the experiment for each trial.
Hints:
Your limiting reagent is either BaCl2 or Na2SO4
calculate # of moles of your limiting reagent from the mass of your precipitate
Trial data:
Mass of unknown: 1.104 g
Actual mass weighted of Na2SO4: 1.425 g
Mass of precipitate: 0.137 g
Homework Answers
Add Answer to:
BaCl2 +Na2SO4 = BaSO4(s) + 2Na +2Cl
Calculate the mass of the limiting reagent that reacted...
using the averaged results of your 2 trials, calculate the mass of the limiting reagent that...
using the averaged results of your 2 trials, calculate the mass of the limiting reagent that reacted in the experiment BaCl2 and NaSO4 are the reactants Liminting reagent is BaCl2 average mass of unknown is 1.090g Average mass of percipitate(BaSO4) is 0.205g
What is the theoretical yield of H2SO4 + BaCl2 ---> BaSO4 + 2HCl Given data: Concentration...
What is the theoretical yield of H2SO4 + BaCl2 ---> BaSO4 +
2HCl
Given data:
Concentration of BaCl2 = 0.20 M
Concentration of H2SO4 = 6 M
volume of H2S04 = 5.00 mL
What is the theoretical expected yield of precipitate as
calculated using stoichiometry?
Compare actual yield and theoretical yield. Calculate percent
yield.
Data:
Trial 1: Mass of BaSO4 precipitate = 0.191 g
Trial 2: Mass of BaSO4 precipitate = 0.187 g
What is the Millimoles of BaSO4 for...
Limiting agent for Na2SO4 + BaCl2? Theoritical yield? Part 2: Na2SO4 + BaCl2 Initial mass of...
Limiting agent for Na2SO4 + BaCl2? Theoritical yield?
Part 2: Na2SO4 + BaCl2 Initial mass of Na 50.:\.009 Predicted mass of Baso, based on mass of Na2SO!! Initial mass of BaClz: 1.01g Predicted mass of BaSO, based on mass of BaCl2: Na2SO4 BaCl2 Limiting reagent: Explain why this is the limiting reagent: Theoretical Yield: Actual mass of Baso, obtained: % Yield for the reaction: different from 100%, why might this be? If this is different from 100%, why
Question 27 3 pts In the limiting reactant" experiment, a mixture of 0.537 g of BaCl2...
Question 27 3 pts In the limiting reactant" experiment, a mixture of 0.537 g of BaCl2 (molar mass - 208 g/mol) and 0.884g Na2SO.(molar mass - 142 g/mol) is added to water and the precipitation reaction occurs in the solution BaCl2t39) + Na2SO4(aq) --> BaSO4(s) +2 NaCl (aq) Please calculate: 2) The limiting reactantis hint: limiting reactant: the reactant that is not enough in the amount please calculate the amount of one reactant from the amount of the other reactant...
10.1 Precipitation of Barium Sulfate-Pre-Lab Questions Name Date: Instructor 1. Calculate the formula weight of BaSO4.(Enter...
10.1 Precipitation of Barium Sulfate-Pre-Lab Questions Name Date: Instructor 1. Calculate the formula weight of BaSO4.(Enter unit as g/mol.) 2 What mass of BasO4 is presont in 40.0 mL of a 0.65 M solution? 3. What is the formula weight of Na SO? (Enter unit as g/mol.) 4. What mass of Na SO4 is present in 100.0 mL of a 0.35 M solution? 5. What is the formula weight of BaC2? (Enter unit as g/mol.) 6. You mix 6.0 mL...
please help with the calculations and limiting reagent\percent yeild!!! molarity of FeCl3 is .40 g/mol we...
please help with the calculations and limiting reagent\percent
yeild!!!
molarity of FeCl3 is .40 g/mol
we
had 5.0 mL of FeCl3 (0.40g/mL) which equals 0.08g divided by 162.2g
FeCl3 which equals 0.000493 moles or 4.9 x 10^-4
EXPERIMENT REPORT SHEET Synthesis of KzFe(C204)3.3 H20 15.0 mL 4a5a watch glass 43.958 : paper Experimental Data Volume of FeCl, solution Mass of K C,04H2O Mass of product 47.891 Calculations Moles of FeCl3 Moles of K C2O4 H2O Moles of product (KsFe(C204)3.3 H20)...
i need help with data Analysis Experiment & Report Sheet Limiting Reactant Desk No. to Lab...
i need help with data Analysis
Experiment & Report Sheet Limiting Reactant Desk No. to Lab Sec. - Lab Sec. Name Precipitation of CaC,OH,O from the Salt Mixture Unknown number_ 2 I Mass of beaker() Mass of beaker and salt mixture (8) Trial Trial 2 3. Mass of salt mixture (8) 4. Mass of filter paper() 5. Mass of filter paper and product after air-dried roven-dried (e) 6. Mass of dried product() (NEE with 0.3889 0.6189 -0.280T0 Cal2o4•H2O 0.998 g...
answer it all please BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will...
answer it all please
BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol...
Based on the data, please answer question 3 (a,b, and c). thank you! CHEM 2115 Limiting...
Based on the data, please answer question 3 (a,b, and c).
thank you!
CHEM 2115 Limiting Reagent Lab Report #6 Chem I Lab Name Mikhayla D'Anne Section# Station# A5 Date 1%4/19 Overall equation: CaCl (aq) + K:C:04H:0 (aq) = CaC,O4+H20 (8) +2 KCI (aq) Net lonic Equation: Ca"? (aq) + CO. (aq) + H20 (1 = CaC20. H:0 (5) 1. Data & Calculations : CaCl K2C2O4+H2O Concentration of solution 0.75 mol/L Volume of solution 15 ml Moles of CaCl2 used...
how can i calculate the theroetical yield for dibenzalacetone? Reagent Data for Part 2: List of...
how can i calculate the theroetical yield for
dibenzalacetone?
Reagent Data for Part 2: List of all reagents.cat Weight, amount used in m ore number of males and limiting reagent should be alysts and solvents. For reagents and catalysts, the molecular niting reagent should be tabulated. Substance Molar mass Grams or mL Moles or Density (if a (g/mol) mmoles liquid) benzaldehyde 106. 12 g/mol 5.10mL 0.0502mols 1.044g/mL acetone 58.08g Imol 2.00mL 10.0274 moles 0.791 glomL NaOH 39.997 g/mol 50 mL...
What is the theoretical yield of H2SO4 + BaCl2 ---> BaSO4 +
2HCl
Given data:
Concentration of BaCl2 = 0.20 M
Concentration of H2SO4 = 6 M
volume of H2S04 = 5.00 mL
What is the theoretical expected yield of precipitate as
calculated using stoichiometry?
Compare actual yield and theoretical yield. Calculate percent
yield.
Data:
Trial 1: Mass of BaSO4 precipitate = 0.191 g
Trial 2: Mass of BaSO4 precipitate = 0.187 g
What is the Millimoles of BaSO4 for...
Limiting agent for Na2SO4 + BaCl2? Theoritical yield?
Part 2: Na2SO4 + BaCl2 Initial mass of Na 50.:\.009 Predicted mass of Baso, based on mass of Na2SO!! Initial mass of BaClz: 1.01g Predicted mass of BaSO, based on mass of BaCl2: Na2SO4 BaCl2 Limiting reagent: Explain why this is the limiting reagent: Theoretical Yield: Actual mass of Baso, obtained: % Yield for the reaction: different from 100%, why might this be? If this is different from 100%, why
Question 27 3 pts In the limiting reactant" experiment, a mixture of 0.537 g of BaCl2 (molar mass - 208 g/mol) and 0.884g Na2SO.(molar mass - 142 g/mol) is added to water and the precipitation reaction occurs in the solution BaCl2t39) + Na2SO4(aq) --> BaSO4(s) +2 NaCl (aq) Please calculate: 2) The limiting reactantis hint: limiting reactant: the reactant that is not enough in the amount please calculate the amount of one reactant from the amount of the other reactant...
10.1 Precipitation of Barium Sulfate-Pre-Lab Questions Name Date: Instructor 1. Calculate the formula weight of BaSO4.(Enter unit as g/mol.) 2 What mass of BasO4 is presont in 40.0 mL of a 0.65 M solution? 3. What is the formula weight of Na SO? (Enter unit as g/mol.) 4. What mass of Na SO4 is present in 100.0 mL of a 0.35 M solution? 5. What is the formula weight of BaC2? (Enter unit as g/mol.) 6. You mix 6.0 mL...
please help with the calculations and limiting reagent\percent
yeild!!!
molarity of FeCl3 is .40 g/mol
we
had 5.0 mL of FeCl3 (0.40g/mL) which equals 0.08g divided by 162.2g
FeCl3 which equals 0.000493 moles or 4.9 x 10^-4
EXPERIMENT REPORT SHEET Synthesis of KzFe(C204)3.3 H20 15.0 mL 4a5a watch glass 43.958 : paper Experimental Data Volume of FeCl, solution Mass of K C,04H2O Mass of product 47.891 Calculations Moles of FeCl3 Moles of K C2O4 H2O Moles of product (KsFe(C204)3.3 H20)...
i need help with data Analysis
Experiment & Report Sheet Limiting Reactant Desk No. to Lab Sec. - Lab Sec. Name Precipitation of CaC,OH,O from the Salt Mixture Unknown number_ 2 I Mass of beaker() Mass of beaker and salt mixture (8) Trial Trial 2 3. Mass of salt mixture (8) 4. Mass of filter paper() 5. Mass of filter paper and product after air-dried roven-dried (e) 6. Mass of dried product() (NEE with 0.3889 0.6189 -0.280T0 Cal2o4•H2O 0.998 g...
answer it all please
BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol...
Based on the data, please answer question 3 (a,b, and c).
thank you!
CHEM 2115 Limiting Reagent Lab Report #6 Chem I Lab Name Mikhayla D'Anne Section# Station# A5 Date 1%4/19 Overall equation: CaCl (aq) + K:C:04H:0 (aq) = CaC,O4+H20 (8) +2 KCI (aq) Net lonic Equation: Ca"? (aq) + CO. (aq) + H20 (1 = CaC20. H:0 (5) 1. Data & Calculations : CaCl K2C2O4+H2O Concentration of solution 0.75 mol/L Volume of solution 15 ml Moles of CaCl2 used...
how can i calculate the theroetical yield for
dibenzalacetone?
Reagent Data for Part 2: List of all reagents.cat Weight, amount used in m ore number of males and limiting reagent should be alysts and solvents. For reagents and catalysts, the molecular niting reagent should be tabulated. Substance Molar mass Grams or mL Moles or Density (if a (g/mol) mmoles liquid) benzaldehyde 106. 12 g/mol 5.10mL 0.0502mols 1.044g/mL acetone 58.08g Imol 2.00mL 10.0274 moles 0.791 glomL NaOH 39.997 g/mol 50 mL...
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