Question

BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol mark Maximum (theoretical) yield of isoamyl acetate at chosen experimental scale mol l mark 2 marks 2 marks 2 marks Molecular formula of isoamyl acetate .. Molecular weight of isoamyl acetate g mol Theoretical yield of isoamyl acetate Density of isoamyl acetate o.88 g ml-i .: Theoretical yield of isoamyl acetate Experimental yield of isoamyl acetate = ml 2 marks ml 2 marks Experimental yield x 100 = x 100 = Theoretical yield 2 marks l mark l mark Appearance of sample Boiling point of sample Literature value of boiling point: Literature reference used mar Remember to submit your sample in a suitably labelled sealed sample
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Answer 1

To calculate %theoretical yield of isoamyl acetate, divide the observed experimental yield with the theoretical yield calculated here, and multiply this with 100.

To calculate %theoretical yield of isoamyl acetate, divide the observed experimental yield with the theoretical yield calculated here, and multiply this with 100. Volume of acitic acid = 7 ml Density of acitic acid = 1 . 05 g/ml mass of acitic acid = volume times density = 7 times 1 . 05 = 7 . 35 gm moles of acitic acid = mass/molecular mass = 7 . 35/60 = 0 . 1225 mol volume of isoamyl alcohol = 11 ml density of isoamyl alcohol = 0 . 81 g/ml mass of isoamyl alcohol = 11 times 0 . 81 = 8 . 91 g moles of isoamyl alcohol = 8 . 91/88 = 0 . 10125 mol mol (A) = 0 . 1225 mol (B) = 0 . 10125 Limiting reagent: isoamyl alcohol = mol (B) Therefore scale of reaction = 0 . 10125 mol