Question

find limiting reagent?

acetone 3.63 mL
benzaldehyde 10.5mL

bp (°C) mol. wt. (g/mole) 58.08 density (g/mL) 0.791 56 106.23 178-179 1.044 Acetone Benzaldehyde NaOH Dibenzalacetone 40.00 234.30 mp 110-111

Answer 1

its Reaction - CHO 2 10 + CH₃COCH? Nady lesser amount Here aceone is lingiting reagent Now reaction will take place trong acedone. reehona Nan dibenzaban boni dibenzdacetone Moss of acetones Vol x density - - 3.63 x 0.797 = 2.878m Mais et benzoldelydes 10 SX 9.099 = 10.96 gan 2 Benneddetycle t 0 - 103 m) 0.0 tyrando Arrection Limiting regent 0 0.0995 0.103-2x0495ml Md et are hones 2.87 = 0.0495 Attr raction mebore = o Benzaldehyde = Mol of benzaldens = 10.96 -0.103 from reachion- 2 mol benzaldehyde reacts with role aceline Mal 1922 11 in 5 mol ) tol 0.002 mol. 106.2 dibenzolaceone = - 0.0495 tot > 0.103 Mel " " SX 103 b oos 17 Mole - but only 0.0495 Mole at present hence are one aceline is in.