Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...

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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 16.0 g of aluminum and 21.0 g of chlorine gas.

If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, Cl2?

Express your answer to three significant figures and include the appropriate units.

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Answer 1

Answer #1

2A1 (s) + 3Cl2 (g) - 2A1C13 (5) molar mas 27.0 133.3 70.9 (in glmoi mas of chlorine gas = 21-09 I moles of cl. produce a mole

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Answer 2

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