Question

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 13.0 g of aluminum and 18.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 13.0 g of aluminum? Express your answer to three significant figures and include the appropriate units.

If you had excess aluminum, how many moles of aluminum chloride could be produced from 18.0 g of chlorine gas, Cl2?

Express your answer to three significant figures and include the appropriate units.