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Aluminum reacts with chlorine gas to form aluminum chloride. 2Al(s)+3Cl2(g)→2AlCl3(s) What minimum volume of chlorine gas...

Aluminum reacts with chlorine gas to form aluminum chloride.

2Al(s)+3Cl2(g)→2AlCl3(s)

What minimum volume of chlorine gas (at 298 KK and 217 mmHgmmHg) is required to completely react with 8.48 gg of aluminum?

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Answer #1

2. Al (5) 4 312 (9) → 2 Alclz (s) 2 mol of Ad reacts with 3 mol of che Number of moles of aluminum = molar mass 8.489 27 g/mo

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