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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2A1 (s) + 3C12 (g)--2AICI3 (s) You are given 32.0 g of aluminum and 37.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 32.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. View Available Hint(s)

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