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concentration of Ca(OH)2 in the solution! 7. Given the following equation: 2 Nacio3 B 2 NaCl...
7. Given the following equation: 2 NaClO3 2 2 NaCl + 3 02, if 12.00 moles...
7. Given the following equation: 2 NaClO3 2 2 NaCl + 3 02, if 12.00 moles of NaClO3 reacted in the reaction; a) How many grams of O2 produced? B) How many grams of NaCl are produced when 80.0 grams of O2 are produced? 8. Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2AI + 3Cl2 → 2AlCl3 a) Identify limiting reagent b) How many grams of aluminum chloride could be produced from 34.0g of...
9. For the balanced equation Fe304 + 4H2 3Fe+ 4H20, if the reaction of 0.112 grams...
9. For the balanced equation Fe304 + 4H2 3Fe+ 4H20, if the reaction of 0.112 grams of H2 produces 0.745 grams of H20, what is the percent yield? 10. How many atoms of C are present in 52 grams of sugar C6H12O6?
Please show all work for the following problems, not just answers. Will thumbs up upon completion,...
Please show all work
for the following problems, not just answers. Will thumbs up upon
completion, thank you! :)
Direction - Please show your work for the following problems. (you may need to answer on separate sheet of paper) Part I- Calculate molecular weight (molar mass). Na2SO4 = Feso, . 71120- HC HO: Part VII- Limiting reagent problems. Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction a) Identify limiting reagent b) How many grams of...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2A1 (s) +...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2A1 (s) + 3C12 (g)--2AICI3 (s) You are given 32.0 g of aluminum and 37.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 32.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. View Available Hint(s)
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 16.0 g of aluminum and 21.0 g of chlorine gas. If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units.
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 13.0 g of aluminum and 18.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 13.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. If you had excess aluminum, how many moles of aluminum chloride could be produced from 18.0 g of chlorine...
In the following chemical reaction, 2 mol of A will react with 1 mol of B...
In the following chemical reaction, 2 mol of A will react with 1 mol of B to produce 1 mol of A2B without anything left over: 2A+B→A2B But what if you're given 2.8 mol of A and 3.2 mol of B? The amount of product formed is limited by the reactant that runs out first, called the limiting reactant. To identify the limiting reactant, calculate the amount of product formed from each amount of reactant separately: 2.8 mol A×1 mol...
Thankyou! Consider the following balanced equation: 502(g) + C3H8(9) 3CO2(g) + 4H20(1) If 19.9 moles of...
Thankyou!
Consider the following balanced equation: 502(g) + C3H8(9) 3CO2(g) + 4H20(1) If 19.9 moles of O2(g) and 4.42 moles of CzHg(g) are allowed to react, what is the theoretical yield of CO2(g) in moles? 0 O OOOO 41.0 moles 94.3 moles 36.3 moles 35.3 moles 11.9 moles Consider the balanced equation for the following reaction: 6HCl(aq) + 2Al(s) + 3H2(g) + 2AlCl3(s) How much excess reactant remains in the reaction if 54.1 grams of HCl reacts with 85.8 grams...
Limiting Reactants, Excess Reactant, and % Yield Name H2+Cl2HCI A gaseous mixture containing 7.5 g of H; gas and 9....
Limiting Reactants, Excess Reactant, and % Yield Name H2+Cl2HCI A gaseous mixture containing 7.5 g of H; gas and 9.00 g of Cl2 gas react to form hydrogen chloride gas. а) Which is the limiting reactant? If all the limiting reactant is consumed, how many grams of HCl are produced? How many grams of excess reactant remain un-reacted? b) c) Cl2+3F22CIF Chlorine reacts with fluorine to form gaseous chlorine trifluoride. You start with 50.0g of chlorine and 95.0g of fluorine....
a. 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 19.0 g of aluminum and 24.0 g of chlorine gas.If you had excess aluminum, how...
a. 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 19.0 g of aluminum and 24.0 g of chlorine gas.If you had excess aluminum, how many moles of aluminum chloride could be produced from 24.0 g of chlorine gas, Cl2? b. Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)→CO2(g)+H2O(g) c. 3H2(g)+N2(g)→2NH3(g) 1.08 g H2 is allowed to react with 10.3 g N2, producing 1.04 g NH3. What is the theoretical yield for this reaction under the given conditions? What is the percent yield for...
7. Given the following equation: 2 NaClO3 2 2 NaCl + 3 02, if 12.00 moles of NaClO3 reacted in the reaction; a) How many grams of O2 produced? B) How many grams of NaCl are produced when 80.0 grams of O2 are produced? 8. Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2AI + 3Cl2 → 2AlCl3 a) Identify limiting reagent b) How many grams of aluminum chloride could be produced from 34.0g of...
9. For the balanced equation Fe304 + 4H2 3Fe+ 4H20, if the reaction of 0.112 grams of H2 produces 0.745 grams of H20, what is the percent yield? 10. How many atoms of C are present in 52 grams of sugar C6H12O6?
Please show all work
for the following problems, not just answers. Will thumbs up upon
completion, thank you! :)
Direction - Please show your work for the following problems. (you may need to answer on separate sheet of paper) Part I- Calculate molecular weight (molar mass). Na2SO4 = Feso, . 71120- HC HO: Part VII- Limiting reagent problems. Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction a) Identify limiting reagent b) How many grams of...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2A1 (s) + 3C12 (g)--2AICI3 (s) You are given 32.0 g of aluminum and 37.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 32.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. View Available Hint(s)
Thankyou!
Consider the following balanced equation: 502(g) + C3H8(9) 3CO2(g) + 4H20(1) If 19.9 moles of O2(g) and 4.42 moles of CzHg(g) are allowed to react, what is the theoretical yield of CO2(g) in moles? 0 O OOOO 41.0 moles 94.3 moles 36.3 moles 35.3 moles 11.9 moles Consider the balanced equation for the following reaction: 6HCl(aq) + 2Al(s) + 3H2(g) + 2AlCl3(s) How much excess reactant remains in the reaction if 54.1 grams of HCl reacts with 85.8 grams...
Limiting Reactants, Excess Reactant, and % Yield Name H2+Cl2HCI A gaseous mixture containing 7.5 g of H; gas and 9.00 g of Cl2 gas react to form hydrogen chloride gas. а) Which is the limiting reactant? If all the limiting reactant is consumed, how many grams of HCl are produced? How many grams of excess reactant remain un-reacted? b) c) Cl2+3F22CIF Chlorine reacts with fluorine to form gaseous chlorine trifluoride. You start with 50.0g of chlorine and 95.0g of fluorine....
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