Question

Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 31.0 of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units View Available Hint(s) ValueUnits Submit

Answer 1

The balanced equation is

2 Al + 3 Cl₂ ----> 2 AlCl₃

Number of moles of Cl₂ = 31.0 g / 70.9060 g/mol = 0.437 mole

From the balanced equation we can say that

3 mole of Cl2 produces 2 mole of AlCl3 so

0.437 mole of Cl2 will produce

= 0.437 mole of Cl2 *(2 mole of AlCl3 / 3 mole of Cl2)

= 0.291 mole of AlCl3

Therefore, the number of moles of AlCl3 produced would be 0.291 mole