Question

Part A How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas? Express your answer with the appropriate units. View Available Hint(s) Value Units Submit

Answer 1

Part A:

The balanced reaction will be

CO2(g) + 4H2(g) → CH49) + 2H2O(9)

One mole of CO2 will produce one mole of CH4, since H2 is in excess, hence CH4 is limiting reagent

Therefore, we will get 85.1 moles of Methane or CH4 gas

Part-B

4 moles of H2(g) will produce 2 moles of H2O

Moles of H2(g) needed = 2 * 53.6 = 107.2 moles

Hence, we need 107.2 moles of H2(g) to produced 53.6 moles of water vapor

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