Question

HW 2 Chp5 Item 6
CO2(g) + 4H2(g) --> CH4(g) + 2H2O(g)
Part A: (express the answer with the appropriate units)
How many moles of methane are produced when 48.1 moles of carbon dioxide gast reacts with excess hydgrogen gas?
Part B: (express the answer with the appropriate units)
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 65.1 moles of water vapor?

Answer 1

Part A:

1 mole of CO2 produces 1 mole of CH4 when reacted with excess H2
So 48.1 moles of CO2 produces 48.1 moles of CH4

Part B:

From the equation, 4 moles of H2 with excess CO2 gives 2 moles of water vapor.
So to produce 65.1 moles of H2O we need 65.1 * 4/2 = 130.2 moles of hydrogen

Note: In case you meant grams instead of moles in the questions, the answers will b different. You need to estimate the moles of the gases by dividing themwith respective molecular weights and repeat the above process.