4CO(g) + 8H2(g) -----> 3CH4(g) + CO2(g) + 2H2O(l)
Use the following data as needed to determine ΔH for this reaction.
1.) C(s) + 1/2O2(g) -----> CO(g) ΔH = -110.54 kJ
2.) CO(g) + 1/2O2(g) -----> CO2(g) ΔH = -282.97 kJ
3.) H2(g) + 1/2O2(g) -----> H2O(l) ΔH = -285.85 kJ
4.) C(s) + 2H2(g) -----> CH4(g) ΔH = -74.85 kJ
4CO(g) + 8H2(g) -----> 3CH4(g) + CO2(g) + 2H2O(l) Use the following data as needed to...
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
Hess's Law Given the following data: P(s) + 3/2H2(g) → PH3(g) ΔH°= +5.0 kJ PH3(g) + 2O2(g) → H3PO4(l) ΔH°= -1272.0 kJ 2P(s) + 5/2O2(g) → P2O5(s) ΔH°= -1492.0 kJ H2(g) + 1/2O2(g) → H2O(l) ΔH°= -286.0 kJ calculate ΔH° for the reaction: H3PO4(l) → 1/2P2O5(s) + 3/2H2O(l) ΔH°=?? also please explain how you found the answer
From the following heats of combustion, CH3OH(l) + 3/2O2(g) → CO2(g) + 2H2O(l) ΔHorxn = –726.4 kJ/mol C(graphite) + O2(g) → CO2(g) ΔHorxn = –393.5 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔHorxn = –285.8 kJ/mol Calculate the enthalpy of formation of methanol (CH3OH) from its elements. C(graphite) + 2H2(g) + ½O2(g) → CH3OH(l) Methanol (CH3OH) is an organic solvent and is also used as a fuel in some automobile engines. From...
Consider the exothermic reaction CH4(g)+2O2(g)→CO2(g)+2H2O(g) Calculate the standard heat of reaction, or ΔH∘rxn, for this reaction using the given data. Also consider that the standard enthalpy of the formation of elements in their pure form is considered to be zero. Reactant or product ΔH∘f (kJ/mol) CH4(g) -201 CO2(g) -393.5 H2O(g) -241.8 Express your answer to four significant figures and include the appropriate units.
Use Hess's law and the following data CH4(g) + 2O2(g) → CO2(g) + 2 H2O(g) AH° = -802 kJ mol-1 CH4(8) + CO2(g) —> 2CO(g) + 2 H2(g) AFH° = +247 kJ mol-1 CH4(g) + H2O(g) –> CO(g) + 3H2(g) AFH° = +206 kJ mol-1 to determine A.Hº for the following reaction, an important source of hydrogen gas CH4(8) + +02(8) — CO(g) + 2 H2(8)
Calculate ΔrH for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l) Use the following reactions and given ΔrH's. CH4(g)+O2(g)→CH2O(g)+H2O(g), ΔrH = -284 kJmol−1 CH2O(g)+O2(g)→CO2(g)+H2O(g), ΔrH = -527 kJmol−1 H2O(l)→H2O(g), ΔrH = 44.0 kJmol−1
Given the following data: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l) ΔH = -2600 kJ C2H2(g) + 2H2(g) → C2H6(g) ΔH = -312 kJ 2H2(g) + O2(g) → 2H2O(l) ΔH = -572 kJ Find the ΔH of the following reaction: 4CO2(g) + 6H2O(l) → 2C2H6(g) + 7O2(g)
Calculate ∆Gº for the reaction, CH4(g)+2O2(g)→CO2(g)+2H2O(g), where ∆Gfº=-50.8 kJ/mol for CH4(g), -394 kJ/mol for CO2(g), and -229 kJ/mol for H2O(g).
2. Given the following data: H2O(l) → H2(g) + 1/2O2(g) ΔH° = 285.8 kJ 2HNO3(l) → N2O5(g) + H2O(l) ΔH° = 76.6 kJ 2N2(g) + 5O2(g) → 2N2O5(g) ΔH° = 28.4 kJ Calculate ΔH° for the reaction: 1/2N2(g) + 3/2O2(g) + 1/2H2(g) → HNO3(l) Note that you should be able to answer this one without needing to use any additional information from the thermo table. I've attempted this question multiple times. I am able to get to the simplified eqaution...