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15. (25 pts) If 25.0 mL of 0.300 M benzoic acid (K, -6.50 x 10°°) is...
15. (25 pts) If 50 mL of 0.20 M benzoic acid (K, = 6.5 x 10)...
15. (25 pts) If 50 mL of 0.20 M benzoic acid (K, = 6.5 x 10) is titrated with 0.25 M NaOH, what is the pH after 0 ml, 10 ml, 20 ml, 40 ml and 50 ml of base have been added? (You may use the approximation.). BE SURE TO SHOW ALL CALCULATIONS.
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with...
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with 0.200 M NaOH. What is the pH of the solution when 0.00 mL, 10.0 mL, 12.5 mL, 20.0 mL, 25.0 mL, and 40.0 mL E.S RaWeMA 5.83 x 10 8) have been added? (Ka1= 2.46 x 10, Ka2 ANSWER: 0 mL = 2.315, 10.0 mL= 4.211 (or 4.213), 12.5 mL = 5.422, 20.0 mL 7.410, 25.0 mL = 9.966, 40.0 mL = 12.664 11....
A 25.0 mL sample of 0.150 M benzoic acid is titrated with a 0.150 M NaOH...
A 25.0 mL sample of 0.150 M benzoic acid is titrated with a 0.150 M NaOH solution. What is the pH after the addition of 13.0 mL of NaOH? The Ka of benzoic acid is 6.3x10-5.
25. A 50.0 mL sample of 0.150 M weak acid was titrated with a 0,150 M...
25. A 50.0 mL sample of 0.150 M weak acid was titrated with a 0,150 M NaOH solution. What is the pH after 30.0 mL of the sodium hydroxide solution is added? The Ka of the acid is 1.9x10(3 points) D) 4.78 E) None of these C) 3.03 (A) 4.90 B) 1.34 26. A 25.0 mL sample of 0.25 M hydrofluoric acid (HF) is titrated with a 0.25 M NaOH solution. What is the pH after 38.0 mL of base...
What is the pH at the equivalence point if 25.0 ml of 0.015 M benzoic acid...
What is the pH at the equivalence point if 25.0 ml of 0.015 M benzoic acid (HC7H5O2 , pKa=4.19) is titrated with 0.025 M NaOH?
8) A 25.0 mL sample of 0.150 M benzoic acid is titrated with a 0.150 M...
8) A 25.0 mL sample of 0.150 M benzoic acid is titrated with a 0.150 M NaOH solution. What is the pH at the eq. point? pka= 4.20
Please help and explain the solutions! 1. A 25.0 mL sample of 0.300 M HNO3 is titrated...
Please help and explain the solutions! 1. A 25.0 mL sample of 0.300 M HNO3 is titrated with 0.300 M NaOH. Calculate the pH before the addition of base 2. A 25.0 mL sample of 0.300 M HNO3 is titrated with 0.300 M NaOH. Calculate the pH after the addition of 24.0 mL of 0.300 M NaOH 3. A 25.0 mL sample of 0.300 M HNO3 is titrated with 0.300 M NaOH. Calculate the pH after the addition of 26 mL of 0.300 M NaOH...
Question 2 15 P Weak Acid Titration Calculations. A 25.0 mL aliquot of 0.50 M propanoic...
Question 2 15 P Weak Acid Titration Calculations. A 25.0 mL aliquot of 0.50 M propanoic acid (CH3CH2O2H) is placed in a 250 mL Erlenmeyer flask and titrated with a standardized solution of 0.25 M NaOH. The pKof propanoic acid is 4.88. Calculate the pH of the solution after the addition of the following volumes of acid. Neglect activity. (15 points) a) 0.00 mL of NaOH added: 2.59 b) 50.00 mL of NaOH added: 8.49 c) 75.00 mL of NaOH...
ration 46. A 30.0-ml sample of 0.165 M propanoic acid is titrated with 0.300 M KOH....
ration 46. A 30.0-ml sample of 0.165 M propanoic acid is titrated with 0.300 M KOH. Calculate the pH at each volume of added base: OmL, 5 mL, 10 mL, equivalence point, one-half equivalence point. 20 mL, 25 mL. Use your calculations to make a sketch of the titration curve. ed by
Quest. 7 (30 pts). Benzoic acid (C6H5COOH), 40.0 mL of 0.150 M, is being titrated with 0.300 M potassium hydroxide (KOH...
Quest. 7 (30 pts). Benzoic acid (C6H5COOH), 40.0 mL of 0.150 M, is being titrated with 0.300 M potassium hydroxide (KOH). Calculate the pH a) before any addition of base, b) at the half neutralization (half equivalent) point, and c) at the equivalent point. The Ka of C6H5COOH is 6.5 x 10-5. Use the appropriate tables when necessary.
15. (25 pts) If 50 mL of 0.20 M benzoic acid (K, = 6.5 x 10) is titrated with 0.25 M NaOH, what is the pH after 0 ml, 10 ml, 20 ml, 40 ml and 50 ml of base have been added? (You may use the approximation.). BE SURE TO SHOW ALL CALCULATIONS.
Acid/Base titrations 10. 25.0 mL of 0.100 M H2A (a weak diprotic acid) is titrated with 0.200 M NaOH. What is the pH of the solution when 0.00 mL, 10.0 mL, 12.5 mL, 20.0 mL, 25.0 mL, and 40.0 mL E.S RaWeMA 5.83 x 10 8) have been added? (Ka1= 2.46 x 10, Ka2 ANSWER: 0 mL = 2.315, 10.0 mL= 4.211 (or 4.213), 12.5 mL = 5.422, 20.0 mL 7.410, 25.0 mL = 9.966, 40.0 mL = 12.664 11....
25. A 50.0 mL sample of 0.150 M weak acid was titrated with a 0,150 M NaOH solution. What is the pH after 30.0 mL of the sodium hydroxide solution is added? The Ka of the acid is 1.9x10(3 points) D) 4.78 E) None of these C) 3.03 (A) 4.90 B) 1.34 26. A 25.0 mL sample of 0.25 M hydrofluoric acid (HF) is titrated with a 0.25 M NaOH solution. What is the pH after 38.0 mL of base...
Question 2 15 P Weak Acid Titration Calculations. A 25.0 mL aliquot of 0.50 M propanoic acid (CH3CH2O2H) is placed in a 250 mL Erlenmeyer flask and titrated with a standardized solution of 0.25 M NaOH. The pKof propanoic acid is 4.88. Calculate the pH of the solution after the addition of the following volumes of acid. Neglect activity. (15 points) a) 0.00 mL of NaOH added: 2.59 b) 50.00 mL of NaOH added: 8.49 c) 75.00 mL of NaOH...
ration 46. A 30.0-ml sample of 0.165 M propanoic acid is titrated with 0.300 M KOH. Calculate the pH at each volume of added base: OmL, 5 mL, 10 mL, equivalence point, one-half equivalence point. 20 mL, 25 mL. Use your calculations to make a sketch of the titration curve. ed by
Quest. 7 (30 pts). Benzoic acid (C6H5COOH), 40.0 mL of 0.150 M, is being titrated with 0.300 M potassium hydroxide (KOH). Calculate the pH a) before any addition of base, b) at the half neutralization (half equivalent) point, and c) at the equivalent point. The Ka of C6H5COOH is 6.5 x 10-5. Use the appropriate tables when necessary.
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