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ration 46. A 30.0-ml sample of 0.165 M propanoic acid is titrated with 0.300 M KOH. Calculate the pH at each volume of added
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30 mlo. 165 и рrор симои омik vs . зи маон счаси, съон + За он — сч,щ, ceo Na + ,0 - (0) m www , изоч сон = When no waoh is aconcentration of cations CH₂cu.cooH = 1.95 mmolest . 20 м . б. 04x45 [н] = ск 2 | 4 c - 1.35 xls xo.b4% 15 = O 4000 pH = 3.Hay equivalence point & Vbase used 4.95 = 8.25 me 2x0.3 [Cuellooh I left = 2.475 mmole 38.25 me - 0.0647 M 0.00093 J1:35 Xlo

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