Homework Answers
e)
millimoles of propanoic acid = 30 x 0.165 = 4.95
millimoles of KOH = 25 x 0.300 = 7.5
HC3H5O2 + KOH ----------------> C3H5O2- + H2O
4.95 7.5 0 0
0 2.55 4.95
here strong base KOH remains.
[OH-] = 2.55 / 25 + 30 = 0.0464 M
pOH = -log (0.0464) = 1.33
pH = 12.67
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