5-5-5. In a random sample of 50 college seniors, 18 indicated that they were planning to...
A survey of 1010 college seniors working towards an undergraduate degree was conducted. Each student was asked, "Are you planning or not planning to pursue a graduate degree?" Of the 1010 surveyed, 658 stated that they were planning to pursue a graduate degree. Construct and interpret a 98% confidence interval for the proportion of college seniors who are planning to pursue a graduate degree. (0.616,0.686): we are 98% confident that the proportion of college seniors who are planning to pursue...
A random sample of ?=80 in-coming college freshmen showed that 44 were planning to bring a car with them to campus next fall. Suppose that we are interested in forming a confidence interval at 95 percent for the proportion of all in-coming college freshmen who are planning to bring a car to campus next fall. Where appropriate, express your answer as a proportion (not a percentage). Round answers to three decimal places. Estimate: _______ Standard error: ________ Multiplier:_________
A random sample of ?=80n=80 in-coming college freshmen showed that 44 were planning to bring a car with them to campus next fall. Suppose that we are interested in forming a confidence interval at 90 percent for the proportion of all in-coming college freshmen who are planning to bring a car to campus next fall. Where appropriate, express your answer as a proportion (not a percentage). Round answers to three decimal places. (a) The estimate is: . (b) The standard error...
(17 points) A random sample of ?=80n=80 in-coming college freshmen showed that 32 were planning to bring a car with them to campus next fall. Suppose that we are interested in forming a confidence interval at 99 percent for the proportion of all in-coming college freshmen who are planning to bring a car to campus next fall. Where appropriate, express your answer as a proportion (not a percentage). Round answers to three decimal places. (a) The estimate is: . (b) The...
In a random sample of 660 full time workers, 132 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker(but didn't). Compute and interpret a 99% confidence interval for the true proportion of workers so angered in the last year that they wanted to hit a colleague.
Problem 3. (17 points A random sample of 80 in-coming college freshmen showed that were planning to bring a car with them to campus next fail. Suppose that we are interested informing a confidence interval at 90 percent for the proportion of all incoming college freshmen who are planning to bring a car to campus next fall Where appropriate, express your wer a proportion not a percentage. Round answers to three decimal places The estimates The standard errors The mutipli...
Suppose that a random sample of 100 part-time college students is 68% female. In this activity, we calculate the 95% confidence interval for the proportion of all part-time college students that are female. Recall that the 95% confidence interval is: sample proportion ± 2(SE) where SE is the standard error (or standard deviation). question 2: State the confidence interval. Then convert the values to percentages and interpret the confidence interval in context.
5. For a random sample of 50 households with gas stoves monitored over a week, the sample mean CO2 level (ppm) in the households was -654.16, and the sample standard deviation was s 164.43. a. Check if the CLT (central limit theorem) applies and show the two assumptions that you check. b. Calculate a 95% (two-sided) confidence interval for true average CO2 level in the population of households with gas stoves. c. Interpret your CI from b. d. Suppose the...
A 2007 Harris poll took a random sample of 1241 Americans and found that 493 of them believed that the profession of teaching "has very great prestige". Find and interpret a 98% confidence interval for the true proportion of Americans who believe that the teaching profession "has very great prestige. Find and interpret a 98% confidence interval for the true proportion of Americans who believe that the teaching profession "has very great prestige."
A survey of 34,754 adults in 2003 indicated that 20.1% of adults were current smokers. A similar study conducted in 1992 of 44,000 adults indicated that 21.5% were current smokers. a. Find and interpret a point estimate of the difference between the proportion of current smokers in 1992, and the proportion of current smokers in 2003. b. A 95% confidence interval for the true difference is (-0.02, -0.008). Interpret. c. What assumptions must you make for the confidence interval in...