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CHM2046L: General Chemistry and Oualitative Analysis II; Fall 2019 Equilibrium: Determination of Acid Ionization Constant (Ka
3. Determine the Kh for CN-at 25°C. The K, for HCN is 4.9 x 10-10 6. Determine the kg of an acid whose 0.294 M solution has a
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1. HNO3 is a strong acid. So, [H +) = (HNO3] = 0.023m. pH = -log[*] = -log (0.023) = (1.64] -14 2. (H30+) [OH-] = Kw = 1:00x1HUID = 0.265 H2O+ + 2107 Initial: __ +x Change: -x Equilibrium: 0.265-x +x x Ka - - 2.9x10 [H30*) (40). 2.9x108 [Hoo] (2) (L)pH = 495 -4.95 - Log (ht] = 4.95 or [4+] = 107 = 12 xiom Initial: HCN - H+ + CN- 0.255 Change : x 1 +2 +2 Equilibrium: 0-255-

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