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Experiment Initial Rate (M/s) [N205(g)] (M) 0.225 0.450 0.0500 0.200 3rd attempt du See Periodic Ta Determine the order of th

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Answer #1

Let the order of N2O5 be x

Then rate law is:

Rate = k [N2O5]^x

From Experiment 1:

Rate = k [N2O5]^x

0.0500 = k (0.225)^x

From Experiment 2:

Rate = k [N2O5]^x

0.200 = k (0.450)^x

Divide eon 2 by eon 1:

0.200/0.0500 = (0.450/0.225)^x

4 = (2)^x

2^2 = 2^x

So,

x = 2

Answer: 2

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