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The angular position of a rod varies as 21.712 radians from time . The rod has two beads on it as shown in the following figu
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Answer #1

given that

\Theta = angular position = 21.7 t^2 rad

a) angular speed w = d\Theta/dt = 2*21.7t = 43.4 t rad/s

at t = 9 sec

w = 173.6 rad/s

b) angular acceleration = dw/dt = 43.4 rad/s^2

c) tangential speed v = rw

at t = 9 sec

vt,1 = 0.13*43.4*9 = 50.8 m/s

vt,2 = 0.34*43.4*9 = 59.02 m/s

d) tangential acceleration

at = r*alpha

at,1 = 0.13*43.4 = 5.64 m/s^2

at,2 = 0.34*43.4 = 14.76 m/s^2

e) centripetal acceleration ac = v^2/r

ac,1 = 50.8^2/0.13 = 19851.1 m/s^2

ac,1 = 59.02^2/0.34 = 10245.2 m/s^2

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