Question

An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is its angular acceleration in rad/s2, rad/s2 (b) What is the tangential acceleration (in m/s2) of a point 9.00 cm from the axis of rotation? m/s2 (c) What is the radial acceleration in m/s2 and multiples of g of this point at full rpm? a in m/s m/s2 a as a multiple of g 9

Answer 1

n An Ultracentrifuge accelerates from sest to 100,000 apon in 2 min. of (a) First we will convert rpm to rad's. 100 000 (270) : 10472 radls' 60 Angular acceleration is given by, x = lf 174.5 10472 rad's 2 6ος rad/52 (6) Tangential acceleration of a Point 9 cm from the sotation axls. 174.5 (94162) = 15.70 m/s2 at =xra why (e) The radial accerelation is given by the formula, q= (10472) ² (0.09) = 9.8 x10 m/s2 In terms of ģet well be 6 9.8x106 m/s² 1410 g 9.8 m/s² "ia = 9.88 108 m/s² a = 100g