Question

Help with part c, please! An ultracentrifuge accelerates from rest to 103100 rpm in 1.75 min. Randomized Variables f = 103100 rpm t = 1.75 min l = 9.7 cm

(9%) Problem 5: An ultracentrifuge accelerates from rest to 103100 rpm in 1.75 min Randomized Variables f= 103100 rpm t = 1.75 min l= 9.7 cm 33% Part (a) What is its angular acceleration in rad/s2? a 102.77 a 102.8 Correct! 33% Part (b) What is the tangential acceleration of a point 9.7 cm from the axis of rotation in m/s2? a, 10.19 Correct! 33% Part (c) What is the centripetal acceleration in multiples of g of this point at full speed? alg = ENE sin cotan( atan cosh J 7 89 E A4 5 cos( asin acotan tanh tan acos sinh cotanh( НОME 6 1 3 0 + END Radians Degrees VOBACKSPACE DEL CLEAR

Answer 1

Solution:

we have full speed (w) = 103100 rpm = 10796.606 rad/s

So, Centripetal acceleration = w² r = (10796.606 rad/s)² (0.097 m) = 11.3 x 10⁶ m/s²

So, a_c = (11.3 x 10⁶ m/s² ) { g / (9.8 m/s²) } = ( 1.154 x 10⁶) g