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(13%) Problem 7: An object 1.4 cm high is held 2.95 cm from a person's cornea,...
(13%) Problem 5: An object of height 2.9 cm is placed 29 cm in front of...
(13%) Problem 5: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 17 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. - A 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. Grade Summary Deductions 0% Potential 100% 1 E sin( cos() tan() cotan() asin() acos atan acotan sinh cosh() |...
(6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in...
(6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in front of a thin converging lens with focal length 6.75 cm, as shown The focal point locations are indicated by the small black circles. A 20% Part (a) Calculate and enter a value for the distance between the image and the lens given the values in problem statement. di = cm Grade Summary Deductions 0% Potential 100% п 7 8 9 HOME E TA...
- 13.4 cm (13%) Problem 3: A ray of light, emitted beneath the surface of an...
- 13.4 cm (13%) Problem 3: A ray of light, emitted beneath the surface of an unknown liquid with air above it, undergoes total internal reflection as shown in the figure. 15.0 cm Otheexpertta.com >> A 50% Part (a) What is the minimum index of refraction for the liquid? n1 min = 1 Grade Summary Deductions Potential 100% 0% ( o E sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh) | tanh() | cotanh) | Degrees Radians 7...
(13%) Problem 7: Consider a parallel plate capacitor having plates of area 1 .25 cmŕ that...
(13%) Problem 7: Consider a parallel plate capacitor having plates of area 1 .25 cmŕ that are separated by 0.016 mm of neoprene rubber. You may assume the rubber has a dielectric constant x- 6.7. > 50% Part (a) What is the capacitance in μF? Grade Summary Deductions Potential 0% 100% cotan atan cosh acos sinh( tanh) cotanhh 4 5 6 1 2 3 0 Submissions Attempts remaining: 6 (3% per attempt) detailed view asin acotan o Degrees oRadians DELCLEA...
14%) Problem 4: An object of height 3.3 cm is placed 4.8 cm in front of...
14%) Problem 4: An object of height 3.3 cm is placed 4.8 cm in front of a converging lens of focal length 23 cm. all parts > 50% Part (a) What is the image distance, in centimeters? Include its sign. Grade Summary Deductions Potential 100 sin cos tan cotan) asino acos atan acotan sinh cosh tanh cotanh Degrees Radians ) 7 8 4 5 1 2 + - 0 VO BACKSPACH 9 6 3 . HOME - - END CLEAR...
(13%) Problem 6: Consider an appliance that consumes 4.75 kW.h of energy per day. > A...
(13%) Problem 6: Consider an appliance that consumes 4.75 kW.h of energy per day. > A 50% Part (a) What is the average power consumption, in watts, of the appliance? P= o E sin() cos tan() cotan() asin() acos() atan() acotan() sinh) cosh() | tanh() cotanh() Degrees Radians ( 7 8 ^^^V 4 5 * 1 2 + - 0 VO BACKSPACE 9 6 3 . DEL Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining:...
(17%) Problem 9: An object of height 2.2 cm is placed 29 cm in front of...
(17%) Problem 9: An object of height 2.2 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and Il cm from it, there is a converging lens of the same focal length. * 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. s"= 22.89 Grade Summary Deductions Potential HOME sin cos t an cotan asin) acos atan acotan() sinh Cosh0 tanh) Coanh)....
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image...
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...
(906) Problem 8: Light of wavelength -536 nm passes through a single slit of width w...
(906) Problem 8: Light of wavelength -536 nm passes through a single slit of width w =2.1 um and illuminates a screen L= 1.7 m away. t material, 50% Part (a) What is the maximum number of dark fringes neinges of light could this setup produce on the sereen? Grade Summar fringes 8 Deductions Potential sin() cos) tan) 7 HOME Submissions asin) acos) cotan) E 1 4 5 6 Attempts remains (4%% per attempt) detailed view atan) sinh) d acotan)...
(14%) Problem 7: Suppose a tightrope walker creates a tension of 3.94 x 103 N making an angle of 5° below the horizonta...
(14%) Problem 7: Suppose a tightrope walker creates a tension of 3.94 x 103 N making an angle of 5° below the horizontal from each supporting pole Calculate how much this tension stretches the steel wire if it was originally 16 m long and 0.43 cm in diameter. Assume steel has a Young's modulus of 2.10 x 101 N/m2. Give your answer in cm. Grade Summary AL = 0.31 Deductions 3% Potential 97% sin( cotan cos Submissions tan 7 НОМE...
(13%) Problem 5: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 17 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. - A 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. Grade Summary Deductions 0% Potential 100% 1 E sin( cos() tan() cotan() asin() acos atan acotan sinh cosh() |...
(6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in front of a thin converging lens with focal length 6.75 cm, as shown The focal point locations are indicated by the small black circles. A 20% Part (a) Calculate and enter a value for the distance between the image and the lens given the values in problem statement. di = cm Grade Summary Deductions 0% Potential 100% п 7 8 9 HOME E TA...
- 13.4 cm (13%) Problem 3: A ray of light, emitted beneath the surface of an unknown liquid with air above it, undergoes total internal reflection as shown in the figure. 15.0 cm Otheexpertta.com >> A 50% Part (a) What is the minimum index of refraction for the liquid? n1 min = 1 Grade Summary Deductions Potential 100% 0% ( o E sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh) | tanh() | cotanh) | Degrees Radians 7...
(13%) Problem 7: Consider a parallel plate capacitor having plates of area 1 .25 cmŕ that are separated by 0.016 mm of neoprene rubber. You may assume the rubber has a dielectric constant x- 6.7. > 50% Part (a) What is the capacitance in μF? Grade Summary Deductions Potential 0% 100% cotan atan cosh acos sinh( tanh) cotanhh 4 5 6 1 2 3 0 Submissions Attempts remaining: 6 (3% per attempt) detailed view asin acotan o Degrees oRadians DELCLEA...
14%) Problem 4: An object of height 3.3 cm is placed 4.8 cm in front of a converging lens of focal length 23 cm. all parts > 50% Part (a) What is the image distance, in centimeters? Include its sign. Grade Summary Deductions Potential 100 sin cos tan cotan) asino acos atan acotan sinh cosh tanh cotanh Degrees Radians ) 7 8 4 5 1 2 + - 0 VO BACKSPACH 9 6 3 . HOME - - END CLEAR...
(13%) Problem 6: Consider an appliance that consumes 4.75 kW.h of energy per day. > A 50% Part (a) What is the average power consumption, in watts, of the appliance? P= o E sin() cos tan() cotan() asin() acos() atan() acotan() sinh) cosh() | tanh() cotanh() Degrees Radians ( 7 8 ^^^V 4 5 * 1 2 + - 0 VO BACKSPACE 9 6 3 . DEL Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining:...
(17%) Problem 9: An object of height 2.2 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and Il cm from it, there is a converging lens of the same focal length. * 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. s"= 22.89 Grade Summary Deductions Potential HOME sin cos t an cotan asin) acos atan acotan() sinh Cosh0 tanh) Coanh)....
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...
(906) Problem 8: Light of wavelength -536 nm passes through a single slit of width w =2.1 um and illuminates a screen L= 1.7 m away. t material, 50% Part (a) What is the maximum number of dark fringes neinges of light could this setup produce on the sereen? Grade Summar fringes 8 Deductions Potential sin() cos) tan) 7 HOME Submissions asin) acos) cotan) E 1 4 5 6 Attempts remains (4%% per attempt) detailed view atan) sinh) d acotan)...
(14%) Problem 7: Suppose a tightrope walker creates a tension of 3.94 x 103 N making an angle of 5° below the horizontal from each supporting pole Calculate how much this tension stretches the steel wire if it was originally 16 m long and 0.43 cm in diameter. Assume steel has a Young's modulus of 2.10 x 101 N/m2. Give your answer in cm. Grade Summary AL = 0.31 Deductions 3% Potential 97% sin( cotan cos Submissions tan 7 НОМE...
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