14%) Problem 4: An object of height 3.3 cm is placed 4.8 cm in front of...
(13%) Problem 5: An object of height 2.9 cm is placed 29 cm in front of a diverging lens of focal length 17 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. - A 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. Grade Summary Deductions 0% Potential 100% 1 E sin( cos() tan() cotan() asin() acos atan acotan sinh cosh() |...
(17%) Problem 9: An object of height 2.2 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and Il cm from it, there is a converging lens of the same focal length. * 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. s"= 22.89 Grade Summary Deductions Potential HOME sin cos t an cotan asin) acos atan acotan() sinh Cosh0 tanh) Coanh)....
(6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in front of a thin converging lens with focal length 6.75 cm, as shown The focal point locations are indicated by the small black circles. A 20% Part (a) Calculate and enter a value for the distance between the image and the lens given the values in problem statement. di = cm Grade Summary Deductions 0% Potential 100% п 7 8 9 HOME E TA...
(13%) Problem 7: An object 1.4 cm high is held 2.95 cm from a person's cornea, and its reflected image is measured to be 0.169 cm high. > 33% Part (a) What is the magnification? m= 1 Grade Summary Deductions Potential 100% 0% o E sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh) | tanh() | cotanh() | Degrees Radians ( 7 8 9 HOME 4 5 6 1 2 3 | + |-| 0 | || END...
(25%) Problem 4: A shopper standing 3.25 m from a convex security mirror sees his image with a magnification of 0.275. 33% Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? d; = -0.89 d;=-0.89 Correct! 33% Part (b) What is the focal length of the mirror, in meters? f = -0.821 sino cos tan() cotan asino acos atan) acotan sinh cosh tanh) cotanh) Degrees Radians...
(11%) Problem 9: A certain slide projector has a 100 mm focal length lens. > * 33% Part (a) How far away is the screen in meters, if a slide is placed 110 mm from the lens and produces a sharp image? d; = -21 Grade Summary Deductions 6% Potential 94% cancel notext HOME cos tan cotan asino acos atan) acotan() sinh cosh() tanh cotanh() Degrees Radians ( 7 8 9 E 1^ 4 5 6 1 2 3 -...
(13%) Problem 7: Consider a parallel plate capacitor having plates of area 1 .25 cmŕ that are separated by 0.016 mm of neoprene rubber. You may assume the rubber has a dielectric constant x- 6.7. > 50% Part (a) What is the capacitance in μF? Grade Summary Deductions Potential 0% 100% cotan atan cosh acos sinh( tanh) cotanhh 4 5 6 1 2 3 0 Submissions Attempts remaining: 6 (3% per attempt) detailed view asin acotan o Degrees oRadians DELCLEA...
(5%) Problem 8: Consider a 470 nm wavelength blue light falling on a pair of slits separated by 0.035 mm. A At what angle (in degrees) is the first-order maximum for the blue light? Grade Summary Deductions 0% Potential 100% sino TT ( 9 HOME 7 8 45 E 6 cotan atan cosh cos tano asino acos acotan tanh cotanh Degrees O Radians Submissions Attempts remaining: 3 (0% per attempt) letailed view sinho 12 برا + - 0 END NO...
- 13.4 cm (13%) Problem 3: A ray of light, emitted beneath the surface of an unknown liquid with air above it, undergoes total internal reflection as shown in the figure. 15.0 cm Otheexpertta.com >> A 50% Part (a) What is the minimum index of refraction for the liquid? n1 min = 1 Grade Summary Deductions Potential 100% 0% ( o E sin() cos() tan() cotan() asin() acos() atan() acotan() sinh() cosh) | tanh() | cotanh) | Degrees Radians 7...
(20%) Problem 4: The shadow of a pendulum cast on a flat board moves on a straight line. By placing the x-axis on the straight line with the origin at the middle of the total path, the x-coordinate of the shadow is given by the following function: x(t) = 49cos(u), where t is in seconds and x is in centimeters. 425% Part (a) Find the speed, in centimeters per second, of the shadow at t = 1/4 s. VE Grade...