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(17%) Problem 9: An object of height 2.2 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the di
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(a)From lens formula 1 1 1 fp 9 - - - -- q= fp f+ P (-16) (29) -16+29 = -35.69cm The object distance of converging lens is p=

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