let the frequency is f
Now , for the peak emf
peak emf = 2pi * f * B * area * N
255 = 2pi * f * 0.375 * pi * (0.055/2)^2 * 500
solving for f
f = 91.1 Hz = 5466 rpm
the frequency is 5466 rpm
(18%) Problem 2: Suppose a generator has a peak voltage of 255 V and its 500...
(10%) Problem 8: Consider the terminal voltage of a 3.00 V lithium cell in a digital wristwatch that draws 18 mA. ► What is the terminal voltage, V, in volts, if the cell's internal resistance is 2.4 2 ? V= na HOME E sin() cos cotan asin atan) acotan cosh tanh( Degrees tan acos sinh() cotanh Radians 7 8 | 4 5 1 2 0 BACKSPACE 9 6 3 . END DEL CLEAR (10%) Problem 9: Consider an automobile battery...
(14%) Problem 2: A wire carrying 390 A to the motor of a commuter train feels an attractive force of 3.8 x 10-3 N/m due to a parallel wire carrying 5.5 A to a headlight. Randomized Variables 1; = 390 A 12 = 5.5 A F = 3.8 x 10-3 N/m > * How far apart are the wires in meters? r= 0.08681 7 89 HOME л E ^^ 4 5 sin() cos tano cotan asin() acos atan acotan sinh)...
(25%) Problem 2: Consider a person whose body temperature has risen because of a fever. A What is the temperature, in degrees Fahrenheit, of a person with a 39.2°C fever? T[°F] = 1 o ( 7 8 9 HOME E ^^ 4 5 6 sin() cos() tan() cotan() asin() acos() atan) acotan() sinh cosh() tanh) | cotanh() Degrees Radians * 1 2 3 .. → END 0 BACKSPACE DEL CLEAR Submit Hint Feedback I give up!
(6%) Problem 13: A 48 105-kg rocket is accelerating straight up. Its engines produce 1.15 107 N of thrust, and air resistance is 4.7 106 N. Randomized Variables m 4.8 105-kg f=1.15. 107 N fr=4.7 106 N What is the rocket's acceleration, using a coordinate system where up is positive? Grade Summ a 13.8 Deductions Potential Submissions tan 7 8 sin0 cos0 HOME Attempts rema (0% per attemg detailed view asin) acos) 4 6 cotan) sinh) 2 3 atan) acotan)...
(13%) Problem 4: Suppose you have an electric field between two parallel conducting plates separated by 0.45 cm and having a potential difference (voltage) between them of 1.9 x 10* V. 4 What is the strength of such an electric field in newtons per coulomb? Grade Su Deductior Potential coS asin acotan tanh Subnissi Attempts 3% per a detailed cotan atan cosh acos sinh cotanh 4|5 6 * 1 2 3 0 END o Degrees o Radians BACKSPA E CLEA...
(6%) Problem ll: An object with height 0.95 cm is placed a distance 21 cm in front of a thin converging lens with focal length 6.75 cm, as shown The focal point locations are indicated by the small black circles. A 20% Part (a) Calculate and enter a value for the distance between the image and the lens given the values in problem statement. di = cm Grade Summary Deductions 0% Potential 100% п 7 8 9 HOME E TA...
(6%) Problem 14: in the figure. A 73 kg man is being hauled away from a burning building as shown Randomized Variables 73 kg 15c T T2 10° d d 50% Part (a) Calculate the tension T Correct! on the left side of the rope, in newtons, if the man is in static equilibrium. d T-694 d 50% Part (b) Calculate the tension T2 on the right side of the rope, in newtons, if the man is in static equilibrium....
(20%) Problem 3: A nozzle with a radius of 0.16 cm is attached to a garden hose with a radius of 0.91 cm that is pointed straight up. The flow rate through hose and nozzle is 0.55 L/s. Randomized Variables n = 0.16 cm rn=0.91 cm Q=0.55 L/S 50% Part (a) Calculate the maximum height to which water could be squirted with the hose if it emerges from the nozzle in m. ha = 238.75 h2 = 238.8 Correct! >...
(11%) Problem 8: Suppose you want an oboe to produce a fundamental frequency of 116 Hz (which is below the range of a typical oboe) on a day when the temperature is 14.5°C. DA If you treat the oboe as a perfect air column which is open at both ends, how long, in meters, should the oboe be? L=1 Grade Summary Deductions 0% Potential 100% ( E sin cos t an() cotan asin() acos() atan) acotan sinh) cosh() tanh( cotanh()...
(14%) Problem 2: The "lead" in pencils is a graphite composition with a Young's modulus of about 1.10 N/m. * Calculate how much shorter (in mm) the length of the lead becomes in an automatic pencil if you tap it straight into the pencil with a force of 4.8 N. The lead is 0.55 mm in diameter and 61 mm long. Grade Summary AL = 3.391 Deductions 12% Potential 88% sin() cos t an() cotan) asin() acos() atan) acotan sinh)...