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(18%) Problem 2: Suppose a generator has a peak voltage of 255 V and its 500 turn, 5.5 cm diameter coil rotates in a 0.375 T
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Answer #1

let the frequency is f

Now , for the peak emf

peak emf = 2pi * f * B * area * N

255 = 2pi * f * 0.375 * pi * (0.055/2)^2 * 500

solving for f

f = 91.1 Hz = 5466 rpm

the frequency is 5466 rpm

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