Question

Aqueous hydrobromic acid (HB) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium bromide (NaBr) and liquid water (H2O). If 10.9 g of sodium bromide is produced from the reaction of 63.1 g of hydrobromic acid and 13.7 g of sodium hydroxide, calculate the percent yield of sodium bromide. Round your answer to 3 significant figures. x 5 ?

Answer 1

balanced equation is HBV + NaOH . NaBr + Ho howt: 102.841491 role IDentification of Liriting Reagent: Moles of HBr = weight of her - Molar 9988 of HBv : 63.1 9418 80.91 9] roce Linole = locutonoles) 20,7798 roles 107 999.8 Morales Holes of Naot = weight of Nach Holar mass of Nach § 13.7 ons A 40 g) pole = 0.3445 Moles on 34815 Hories among the two Reactants Naoth has less number of es. Thus Nacht is the limiting Reagent.. di among the two

calculation of theoretical Yield: (100% yield): 40 ging of Mach produces 102.894 ong of NaBr 13 7 918 of Nash produces ? gng of NaBr = 13 7 X 102.894 aug of daBr Ho 235 2441 gns of NaBr a theoretical yield = 35.241 978 of NaBr calculation of % of yields J. of yield=: Expertental weight vi & xloo Theoretical weight 10.9 - licf yilida 30.9.). wex lod = 30.989.1.