Question

After reviewing the information in Figures 1 and 2 and the table in the introduction, two students offer the following hypotheses:

  • Student X: The number of fluorine atoms that bond to a metal atom is equal to the number of valence electrons of the metal. The number of fluorine atoms that bond to a nonmetal atom is equal to 8 minus the number of valence electrons of the nonmetal.
  • Student Y: In general, there is an inverse relationship between the electron affinities of the period 3 elements and the number of fluorine atoms that bond to the metal or nonmetal atoms.

Do you agree with Student X's hypothesis, with Student Y's hypothesis, with both of them, or with neither of them? You can use the hints to evaluate the validity of each hypothesis before answering.

Student X's hypothesis is valid,
Student Y's hypothesis is valid,
Both hypotheses are valid,
Neither hypothesis is valid,

<Chapter 8 - Perlodic Trends Data Interpretation and Analysis Exercise 8.141: Periodic Compound Nar MgF2 |AlF3| PF3|SF|CI| Fi

purse Home <Chapter 8 - Periodic Trends Data Interpretation and Analysis Exercise 8.141: Periodic Properties Compound Naf MgF

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Answer #1

Answer to the given question is as follows:Answey = hy potheses Stuclent a X S The numbey of fluorine bondod to a yetal vatom es equal to oumber of valence ele ct roELectnonic cmfigwration rvumber of fluoine-ctoms Element valence electnons >15? 282 2p6 35! Na > Naf mg 1s2 25? 2p632 -> MgPzhypothesis is 7 Thus, the Stadent XS covrect: studentys hypothes es. n vgenorol there is van invoue relationthip betwe en tBut o bser ve element electron vobebinity to y dou out versus -350- 300 -- - 250 -200 (SO - l00 - 50 Ne Na mg element AL -rfhto volecide vocbout itS electron affinity of the contral metal outom es incorrect. > The electnon abfinity odong a period enoelectron. voolal itional to talee am > Hence, ele ctron affinity nobel vgas es have sro cperriool-3) howe tives hoghest voele

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