An aerialist on a high platform holds onto a trapeze attached to a support by an...

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Answer 1

Answer #1

Solution :-

The original height of the platform is given by:

cos(36) = d/6.8 m

d = 5.501 m

Te total height of the aerialist is

H= d+ h=5.501 + 0.74 = 6.241 m

Then , the angle θ that the trapeze cord makes with the vertical at this instant.

cos(θ) = 6.241/6.8

θ= 23.394°

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Answer 2

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