Question

12. The artificial sweetener "NutraSweet' is the compound aspartamine which has the molecular formula C14H18N,Os. a) What is the mass of 1.00 mol of aspartamine? b) How many moles of asparatmine are present in 6.22 g of the substance? c) What is the mass in grams of 0.245 mol of aspartamine? d) How many molecules are present in 4.28 mg of aspartamine?

Answer 1

atomic weight of C =12 g, H=1 gm, O=16 gm, N =14 gm

molecular formula = C₁₄H₁₈N₂O₅

molecular mass M = sum of each mass of atom present in the molecule

molecular mass of aspartamine =mass of C +mass of Hydrogen +mass of O +mass of N

M_C14H18N2O5= 14*12 g+18*1 g+14*2 g+16*5 g

M_C14H18N2O5= 168 g+18g +28g+80g

M_C14H18N2O5= 294 g

1 mole of any substance is equal to its gram molecular mass and contain 6.023 *10²³ molecules

a) mass of 1 mol of aspartamine =294 g

b) mass taken 6.22g

moles n = mass taken(m)/molecular mass (M)

n= m/M

n= 6.22 g/294g= 0.0211 moles

c) 1 mole of C₁₄H₁₈N₂O₅ weighs 294 g

0.245  mol of aspartamine weighs = 294 g*0.245 = 72.03 g

d)1mole or 294 g aspartamine  contain 6.023 *10²³ molecules

1gm of aspartamine  contain 6.023 *10²³/294 molecules

4.28mg = 4.28*10^-3 g  of aspartamine  contain =4.28*10^-3 g *6.023 *10²³/294 molecules [1gm =1000mg]

4.28*10^-3 g  of aspartamine  contain =8.769 *10¹⁸molecules