solution:-
given that n = 50
and mean = 32 , σ = 6
a.the value of 90% confidence from z table is z = 1.645
confidence interval formula
=> mean +/- z * σ/sqrt(n)
=> 32 +/- 1.645 * 6/sqrt(50)
=> (30.6042 to 33.3958)
b.the value of 95% confidence from z table is z = 1.96
confidence interval formula
=> mean +/- z * σ/sqrt(n)
=> 32 +/- 1.96 * 6/sqrt(50)
=> (30.3369 to 33.6631)
c.the value of 99% confidence from z table is z = 2.576
confidence interval formula
=> mean +/- z * σ/sqrt(n)
=> 32 +/- 2.576 * 6/sqrt(50)
=> (29.8142 to 34.1858)
Question 2] A simple random sample of 50 items from a population with o=6! resulted in...
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