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A simple random sample of 40 items resulted in a sample mean of 30. The population standard deviation is o = 15. a. Compute t

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Answer #1

a)

95% confidence interval for \mu is

\bar{x} - Z\alpha/2 * \sigma / sqrt(n) < \mu < \bar{x} + Z\alpha/2 * \sigma / sqrt(n)

30 - 1.96 * 15 / sqrt(40) < \mu < 30 + 1.96 * 15 / sqrt(40)

25.4 < \mu < 34.6

95% CI Is ( 25.4 , 34.6 )

b)

95% confidence interval for \mu is

\bar{x} - Z\alpha/2 * \sigma / sqrt(n) < \mu < \bar{x} + Z\alpha/2 * \sigma / sqrt(n)

30 - 1.96 * 15 / sqrt(90) < \mu < 30 + 1.96 * 15 / sqrt(90)

26.90 < \mu < 33.10

95% CI Is ( 26.90 , 33.10 )

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