Given:
m1 = 6.0151 amu
A1 = 7.5 %
m2 = 7.016 amu
A2 = 92.5 %
use:
atomic mass = sum of (mass of isotope * abundance) / 100
m = (m1*A1 + m2*A2)/100
= (6.0151*7.5 + 7.016*92.5)/100
= 6.9409 amu
Answer: 6.9409 amu
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