A 20.00 mL sample of HCl was titrated with the 0.022 M NaOH solution. To reach...

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Answer 1

Answer #1

Hol & Noon – Nach th₂o Mol doon = ( x V - - (23072x153) *(0.022) 5.2107104 mol stone = mol hcl = 5.21 x le 4 mes 5.2 X10 Ther

Answer 2

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