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For the titration of 50. mL of 0.10 M ammonia with 0.10 M HCl, calculate the pH For ammonia, NH3, Kh = 1.8 x 105. (a) Before

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a) Before any HCl addition NH3 + H₂O - NHyt toh 1. 8 o -5 eqm; C-cd ca ca cicone of Nth = 0.1M 2: degree of dissociation :ka14-2.87 pH = 14-POH LpH = 11-13 After ZomL of 16 0.1 MHCI Zomyx 0.1 mol = 2mmol of Hal NH₂ + HCL NHutch. (Buse (Acid) (salt)d) At equivalence point, all NH3 has been reacted with acid to form salt. 5 mmol of NH3 neutralised by Samol acid to form 5 m

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