u = (x1)0.5 + (x2)0.5
(1)
Budget line: m = p1.x1 + p2.x2
Utility is maximized when MU1/MU2 = p1/p2
MU1 = u/x1 = 0.5 / (x1)0.5
MU2 = u/x2 = 0.5 / (x2)0.5
MU1/MU2 = [0.5 / (x1)0.5] / [0.5 / (x2)0.5] = (x2/x1)0.5 = p1/p2
Squaring,
x2/x1 = p12 / p22
x2 = x1.(p12 / p22)
Substituting in budget line,
m = p1.x1 + p2.[x1.(p12 / p22)]
m = p1.x1 + [x1.(p12 / p2)]
m = x1.[p1 + (p12 / p2)]
m = x1.[(p1.p2 + p12) / p2)]
x1 = (m.p2) / (p1.p2 + p12)
x2 = [(p12 / p22).(m.p2)] / (p1.p2 + p12) = (m.p1) / (p1.p2 + p22)
(2)
If all income is spent on one good, either x1 is zero (everything is spent on x2) or x2 is zero (everything is spent on x1). Since demand function of both goods are independent of the amount of the goods, a corner solution is possible.
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