Question

Question 1 1 pt (References) Draw curved arrows to indicate the movement of electrons in the following reaction. HH HH CH30: --C-CH C=C Br HH aught in the CH2OH course Br. Question 2 Question 3 Question 4 Question 5 Question 6 Question 7 Question 8 Question 1 pt 1 pt 1 pt pt 1 pt 1 pt 1 pt 1pt Arrow.pushing Instructions Question 101 pt roup CH3O:- - Home HH c=c H снҳон :Br: H Br Hem attempts remaining Duo Nov 11 115 PM Previous Next) Fish Assignment

Answer 1

In organic reactions, according to the curved arrow notation , an arrow always originates from a negatively charged species or an electron rich species which means the tail of arrow starts from an electron rich species which attacks a positive species or site . So the head of an arrow will always point towards a species which is either bearing a positive charge or is electron deficient.

Since chor is a negatively charged species so it will attack a positive an electron deficient species of a the other molecule In the second molecule there are c (carbon), (hydrogen) and bere (bromine) atoms. Out of c and th, c is more electronegative than so when this bonded to a it is slightly electropositive as compared to c so t is an electron deficient species in the second molecule. (Br has lone pair of electrons and is more electronegative than c. so it clearly not electron deficient) Therefore, CH₂o- will attack a hydrogen of second molecule.

The second molecule is to ta HR I have numbered the two carbons as t and 2. C-1 is slightly electron rich as it is bonded to 3 hydrogens which are all less electronegative than a while c-2 is slightly electron deficient as it is bonded to br atom u which is more electronegative than c. so chu will attack on t of cate I will leave as it and the two electrons of c-H bond will make a double bond between C-1 and c-2 with simultaneous elimination of Bee Bere will take away the two bonded electrons of the c-Ber bond This can ~ be shown as: _the Choo + Br + Choth

NOTE :

( In case of bonded electrons , the tail of arrow originates from the bonded electrons and the head of arrow points towards the species which takes away the bonded electrons . For example in case of Br leaving as Br^{​​​​​-} )