i missed this question on a chem test recently, and im not quiet sure how to...
Gen Chem I Fa17 York, Exam 2 Show all work, include units as appropriate 1. Use the given standard enthalpies of formation to calculate AH° for the following reaction: CH4(9) + 4C4;() --> CC14(g) + 4HCl(3) Species AH', kJ/mol CH4(g) -74.6 Cl2(g) CCL(3) -95.7 HCl(9) -92.3 0
Given these reactions, where X represents a generic metal or metalloid 1) H,(g) + 0,(g) – HO(g) AH = -241.8 kg 2) X(s) + 2 C1,(8) XCI(S) AH = +182.9 kJ 3) H,(8) + CI,(E) — HCI(8) AH; = -92.3 kJ 4) X(8) + 0,(8) — X0,() AHA = -756,5 kJ 5) H.O(g) - HO(1) AHS = -44.0 kJ what is the enthalpy, AH, for this reaction? XCI,(s) + 2 H,001) — XO,(s) + 4 HCl(g) AH =
14) Starting with the Lewis symbol for magnesium, give the chemical equation for the loss of 2 electrons from a neutral magnesium atom. 15) Explain the trends in increasing ionic radii. 16) What has a higher lE, sodium or magnesium and why? (Hint: Hard question, so write out the electron configuration of each then attempt to answer it) 6) Calculate AH for the following reaction: CHA (g) + 4Cl2(g) - CCL () + 4HCI (9) Use the following reactions and...
6-8 Using the table below, calculate the AH rxn for each of the following equations. Selected Standard Enthalpies of Formation at 25° C (298K) AH (kJ/mol) (kJ/mol Formula AH 0 Silver 92.3 Agis) AgC(3) 0 1270 218 Formula AH (kJ/mol Formula Calcium Ca(s) CI (9) Ca(s) 635.1 HC (G) Caco (s)-1206.9 Hydrogen Hig) Carbon C(graphite) 0 H (9) C(diamond) 1.9 Nitrogen COL) -1105 N19) CO(g) -393.5 NH,(g CH_(9) 74.9 NO(9) CH,OHI) -238.6 Oxygen HỎNG) 133 O.) CS.) 87.9 O (9)...
Given these reactions, where X represents a generic metal or metalloid 1)H,(8) + 402(8) — 4,0(8) 2) X(s) + 2 C12(g) → XCI_(5) 3) {H_(9) + Cl2(9) — HCI(9) AH = –241.8 kJ AH2 = +255.5 kJ AHz = -92.3 kJ 4) X(s) + O2(g) → XO_(s) AH4 = -753.1 kJ 5) H2O(g) — H2O(1) AH3 = -44.0 kJ what is the enthalpy, AH, for this reaction? XCI_(s) + 2 H2O(l) → XO2 (s) + 4 HCI(g) AH =
Consider these reactions, where M represents a generic metal. 1. AH = -741.0 kJ AH = -74.8 kJ 2 M(s) + 6 HCl(aq) 2 MCI, (aq) + 3 H, (g) HCI(g) — HCl(aq) H2(g) +CI,() — 2 HCI(8) MCI,(s) – MCI, (aq) 3. AH = -1845.0 kJ 4. AHA = -256.0 kJ Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 C1, (g) — 2 MCI, () AH =
Use the molar bond enthalpy data in the table to estimate the value of AHin for the equation Bond 0-H 0-0 kJ. mol 464 142 351 kJ. mol 890 390 159 CH,() + 4C1,(8) CCI (8) + 4 HCI(g) C-0 The bonding in the molecules is shown. O=0 502 418 C=0 945 730 347 H- Bond CEN N-H N-N N=N N=N F-F CI-CI Br-Br H-H H-F H-CI - Cl C-CI + C CI CCI C-CI 155 HC + H Cl...
I hope the answer is clear and correct thanks Question 1 (1 point) What is the change in enthalpy (in kJ mol'?) for the following reaction F2(g) + Cabr,(s) CaF() + Brz(1) O 1) -112 kJmo12 O2) 504 kJmo11 03) -504 kJmol 1 04) 537 kJmo11 O 5) -537 kJmol'i Question 2 (1 point) What is true about the following reaction at 25°C? F,(g) + 2HCl(g) 2 2017(g) + H (9) Ahrº=76 kJ mol'i Asr°=-10.13 J mol'i Ki Agrº=79 kJ...
Use the molar bond enthalpy data in the table to estimate the value of AH x for the equation CCI,() +2F2(g) → CF.(g) + 2 C12(8) The bonding in the molecules is shown. kJ. mol- 890 390 159 418 -945 155 243 FF C-CI F- C- F + F-F Average molar bond enthalpies. (Hbond) Bond kJ. mol-1 Bond O-H 464 CEN 0-0 142 N-H C-o 351 N-N 0=0 502 NEN C=0 730 N=N C-C 347 F-F C=C 615 CI-CI CEC...
Express the enthalpy in kJ Acceptable units Acceptable units X C Get Homework Help With + X um.ecollege.com/course.html?courseld-15350726&OpenVellumHMAC=c1df59a153217665a9f9526c8fe3a8b9# 10001 Course Home <Chapter 6 Exercise 6.82 - Enhanced - with Feedback < 24 of 34 Calculate A H for the following reaction: CH (g)+ 4C2(g) CC4(g) + 4HCI (g) given these reactions and their AH values: C(s) C(s) + 2C12(g) 2H2(g) CH4(g), CCL(g), AH=-74.6 kJ AH-95.7 kJ H2(g) + Cl2(g) 2HCI(g), AH=-184.6 kJ Express the enthalpy in kilojoules to one decimal...