Question

QUESTION Z 125 MARIS 1. Write the equilibrium espression for ch of the following reacties: N 11, tại vì 2 MH MI 2. The disociation of the CHCOOH. has inquilibrium 25Caf1. 810 The actions CH.COOH CH.000 If the equilibrium concentration of CH.COOH is 0.46 moles in 500 Lo wner and that ofCH.CD0 1 0. moles in the same 0.500L. calculate for the ruction 500 m, (Pro) -0.150 ring raction, wts mu 3. Gre the initial partial pressures of (as) - ater, and P 2 50 atm a 250 for the och equilibrium partial pressure bel POPCh. O K , 2.15 4. The reaction NDX + N + D has a value of K 2400 at 2000 i 061 of N e pot in a previously empty 3.00 L vessel call the equilibrium contratos NO, Nando 3/4 7. The following reaction has an equilibrium constant of 620 at a crtain temperature. Calculate the equilibrium concentracions al species ir 45 molof each component were added to a 3.0 Lask Ha 2 HF & Ammonia under hydrolysis NH, H + H3 + NH4 ording to the following reaction + 0H K = LB - 10 % Calculate INHLINH.) and in a solution galy 0.200 MNH 7. The ultric t or the following reaction 600 CB 40. Initially to make of de mee H emised in a 10 her container. Determine the contrato dal species at equilibrio 00+ HACH B185.0 moof, and 40 of NO were into an empty 1.0 liter flask, calculate the equilibrium constant if the amount of NO, found equilibrium was 15 moles

Answer 1

1) Equilibrium equation is as follows: N,(g) + 3H2(g) + 2NH (8) Equilibrium constant, K _ (numerator] = (denominator] (NH, [N][H,

ICH.COOH) 500L 0.46 mol 2) Concentration of acid CH,COOH,[CH,COOH = 1.12M Concentration of conjugate base,CH,000-1 = 8.1x10 mol = 0.0162M e. 145360 0.500 L PK, of CH,COOH = -log K, = -log(1.8x10-) = 4.74 According to Henderson equation, CH,C00] pH = pk, +log CHỢCOOH] 0.0162 M 20 = 4.74+ log 1.12 M