If a gold wire has a resistance of 65.7 Ω at a temperature of 18.0 oC, what resistance does it have at 76.1 oC? (Neglect any change in length or cross-sectional area resulting from the change in temperature.)
Solution :-
R1 = R × (k + T2) /(K+ T1)
= 65.7× (256.4 +76.1 ) /(256 .4 +18)
= 79.6 ohms
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