Question

the extra question i cant get

3. A concrete cube, 0.5 meters on each side, is lowered beneath the surface of Seneca Lake. At what depth is the water around it exerting an inward force of 1.7x10 newtons on each face of the cube? 69.4m 4. A 0.5 kg block is attached to a spring and oscillates on a horizontal frictionless surface in the usual way with an amplitude of 0.085 meters. The spring constant is 125 N/m and the spring has negligible mass of its own. a) Calculate the period of oscillation. .397 b) Calculate the maximum acceleration of the block. 21.25 Extra: A simple pendulum (on Earth) is 0.5 meters long. If it swings with an amplitude of 0.08 meters, what is the maximum acceleration of the pendulum bob? 1.57m1S²

Answer 1

Solution : the time period of pendulum is

T = 2pi (l/g)^1/2

now acceleration of pendulum =w²A

Where w is angular frequency and A is amplitude.

Now w = 2pi /T

So w² = g/ l

Using this equation

a = 9.81 x 0.08 / 0.5 = 1.569 m/s2 = 1.57 m/s2