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Each problem is worth 2 point for a total of 10 points EXTRA CREDIT Fully depreciate all problems using all three methods (SL
Y6: 18,000 hours Problem #2: Oven Purchased Jan 1 Cost: $90,000 RV: $15,000 Life: 4 years or 50,000 hours Y1: 12,000 hours Y2
Y9: 5,000 hours 7,000 hours Y10: Problem #5: Refrigerator Purchased October 1 Cost: $260,000 RV: $40,000 Life: 5 years or 80,
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Depreciation SL - Depreciable Value Useful LifeSA SA Straightline Method (SL) Asset (A) Forklift Cost (B) 1,80,000.00 Residual value (C) 25,000.00 Depreciable value (D) = (Asset (A) Oven Cost (B) 90,000.00 Residual value (C) 15,000.00 Depreciable value (D) = (B-C) 75,000.00 Year Depreciation = (DAsset (A) Aston Martin Cost (B) 2,60,000.00 Residual value (C) 80,000.00 Depreciable value (D) = (B-C) 1,80,000.00 Year DepreAsset (A) Safe Cost (B) 60,000.00 Residual value (C) 10,000.00 Depreciable value (D) = (B-C) 50,000.00 Year Depreciation = (DAsset (A) Refrigirator Cost (B) 2,60,000.00 Residual value (C) 40,000.00 Depreciable value (D) = (B-C) 2,20,000.00 Year DepreDepreciation Uofp = Depreciable Value Estimated production during useful life life x Units per yearUnit of Production method (UofP) Asset (A) Forklift Cost (B) 1,80,000.00 Residual value (C) 25,000.00 Depreciable value (D) =Asset (A) Oven Cost (B) 90,000.00 Residual value (C) 15,000.00 Depreciable value (D) = (B-C) 75,000.00 Estimated production uAsset (A) Aston Martin Cost (B) 2,60,000.00 Residual value (C) 80,000.00 Depreciable value (D) = (B-C) 1,80,000.00 EstimatedAsset (A) Safe Cost (B) 60,000.00 Residual value (C) 10,000.00 Depreciable value (D) = (B-C) 50,000.00 Estimated production uAsset (A) Refrigirator Cost (B) 2,60,000.00 Residual value (C) 40,000.00 Depreciable value (D) = (B-C) 2,20,000.00 EstimatedDepreciation DDB = 2 x Depreciation SLA EA EA Double Declining Balance (DDB) Asset (A) Forklift Cost (B) 1,80,000.00 Residual value (C) 25,000.00 Depreciable valueAsset (A) Oven Cost (B) 90,000.00 Residual value (C) 15,000.00 Depreciable value (D) = (B-C) 75,000.00 Year Depreciation = 2Asset (A) Aston Martin Cost (B) 2,60,000.00 Residual value (C) 80,000.00 Depreciable value (D) = (B-C) 1,80,000.00 Year DepreAsset (A) Safe Cost (B) 60,000.00 Residual value (C) 10,000.00 Depreciable value (D) = (B-C) 50,000.00 Year Depreciation = 2A A A Asset (A) Refrigirator Cost (B) 2,60,000.00 Residual value (C) 40,000.00 Depreciable value (D) = (B-C) 2,20,000.00 Year

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