Question

Before Collision After Collision D=0 (1/3) [20 points) In each of three experiments, puck A (of mass m) is launched on a frictionless surface with speed v, toward stationary pucks X, Y, and Exp. 1 Z. Pucks X, Y, and Z all have the same mass M, which is greater than the mass of puck A (M > m). X, Y, and Z are made of different materials. Exp. 21 The collisions are not necessarily elastic. In Exp. 1, puck A hits puck X and stops. In Exp. 2, puck A rebounds to the left with speedvo. In Exp. 3, puck A continues to the right with speedV VO (1/6) Exp. 31 A. [4 pts) In Exp. 2, is the magnitude of the change in momentum of puck A (PAD greater than, less than, or equal to the magnitude of the change in momentum of puck Y PYD? Explain. B. [4 pts) In Exp. 2, is the magnitude of the final momentum of puck Y (IPD greater than, less than, or equal to the magnitude of the initial momentum of puck A (PAD)? Explain. C. [6 pts) Rank the final speeds of pucks X, Y, and Z from greatest to smallest. Explain.

Answer 1

(1) In case q experiment UA = No , VA =-110 ly = 0, vy==? Using Ivo 4 conferrehon qui near momentum MVA + MV = m Vo to 3 - m Ve + MPV = m Vo => MV = 4 m Ve Thus change in momentum q leke V Puuko ylpy) Pyle My 4 m Vo and change in momentum q fulka B IPAL = PA-RA = mro-(-mvo) = 4mvo Thuy 1hr1= IPAL Thue the change in momentum q puluc A UPA) is equal to the magnitude 4 the change in momentum q Puck YlPrl] final momentum q puck Y, Pty= MV = ovo and Initial momentum q puuc A PA = MVO < 4mVc i IPA ICY They the magnitude of the final momentum oq puck Yllk) is greater than the magnitude q the initial momentum q pulk APPAL for ( x o Mvo + MXO = mxo + MV » A = m vo lor ( m vo + MXO = -MYO + M Vy >> Wy: MVO

To 6M 3 m Vo + MXo = myo + MVZ = Vz= 5myo Thy Vy> Vx > Vz » Rank of speeds from largest - to smallest is ox>z - Apply conserrahon a momentum and find the final a veloury of puck A to find that the outcome is paul ble or not m Voto=mYA + MVO VA = ( mo ) Vo =- You suiven 3 m-M-49 3m-3M 5-M 3 Mo 4m > Since M>M → permitted (1) Limilarly YA = M-M) No = tvo m-M===> 66-6M= M M=şm<m Since MXM (Given) s so the outcome is forbidden