Question

Trans-crotonic acid C4H6O2) has a pka of 4.69. What is the pH of a 0.035M solution of this acid. (Write answer to the hundredths place)

Answer 1

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HGHz Cu HgOz I(M) C(M) — k = lo-eks IE(M) С-Сх ca CA ka= c(1-0) 1 - c pkg = logka -ca 1 tca +ca =104.692.04x10 [++] [ cu H5O2 ] = Caxca - Cx2 [HC y HGO] as ke is very very oºo (1-6) Ika /2.04x10-5 z 2.41 x 10-20 ✓ 0.035 [H+] = CQ = 0.035x2-414152 = 8-435x10m PH= -log [ht] 3 -log[8.435x104] - ph: 3:07 - or pH = 307 x10-2 Ies Scanned with CamScanner